Troponin-tropomyosin molecules prevents a muscle contraction from occurring when the muscle is at rest.
<h3>What is
muscle contraction?</h3>
The activation of tension-producing regions within muscle cells results in muscular contraction. Because muscle tension can be created without changes in muscle length, such as when holding something heavy in the same position, muscle contraction does not always imply muscle shortening in physiology. Muscle relaxation, or the return of the muscular fibers to their low tension-generating state, occurs after a muscle contraction has finished.
Both length and tension can be used to characterize muscle contractions. If the muscle tension varies but the muscle length doesn't, the muscle contraction is said to be isometric. A muscle contraction is isotonic, however, if the tension in the muscle remains constant during the contraction.
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Answer:
The statement suggests ability of existing DNA molecule to replicate itself by the process of DNA replication. Each strand of double helical DNA can serve as template for the synthesis of new complementary DNA strand.
Explanation:
Watson and Crick proposed the double-helical structure of DNA. Accordingly, the DNA molecule is a double helical structure in which two polynucleotide chains are held together by base pairing between the complementary bases of two chains.
There are four nitrogenous bases present in DNA: adenine and guanine (purines) and cytosine and thymine (pyrimidines). Adenine always pairs with thymine and cytosine pairs with guanine base.
According to Watson and Crick, the ability of one DNA strand to base-pair with a complementary DNA strand suggests the existence of the DNA replication process. During DNA replication, each DNA strand should serve as a template to specify the nucleotide sequence of the new DNA strand.
Given data:
● Angular velocity of the turntable ω = 33 rev/min
Therefore,
ω = 33 rev/min
ω = 33rev/min × 2π rad/rev × 1 min/60 sec = 3.45 rad/s
● The distance of the watermelon seed from the axis of rotation r = 7.8 cm = 0.078 m
● μs = the coefficient of static friction
Section a:
The seed is undergoes circular motion and it is been effected by centripetal acceleration.
ac = rω^2
ac = 0.078 × 3.45^2
ac = 0.9284 m/s^2
Therefore,
the centripetal acceleration of the seed is 9.274 m/s^2
Section b:
If the seed is observed not to slip at the course of the circular motion, then the supplied frictional force given by the seed and surface of turntable would at least be equivalent to the centripetal force working on the seed.
Centripetal Force = Frictional Force
mrω^2 = μsmg
μs = rω^2 /g
μs = 0.078 × 3.45^2
------------
9.81
μs = 0.09464
Thus,
the coefficient of static friction is 0.09464.
Answer: Olight + water + carbon dioxide → oxygen +.
glucose
Explanation
