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2 years ago

Please help with this problem thanks so much

Mathematics

1 answer:

Lunna [17]2 years ago

4 0

Answer:

5/17

Step-by-step explanation:

If we do the multiplication first, we get:

$\frac{4-(12\div-12)}{13+(-8\div-2)}$

If we do the division next, we get:

$\frac{4+1}{13+4} = 5/17$

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Step-by-step explanation:

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3 years ago

Segment AB is being dilated with the center at the origin. The image of A, point A" has coordinates of (3.2, 6.4). What is the s

insens350 [35]

Answer: The correct option is

(A) The scale factor is 0.8 and the coordinates of point B" are (–3.2, –4.8).

Step-by-step explanation: Given that the segment AB is being dilated to A''B'' with the center at the origin. The image of A, point A" has coordinates of (3.2, 6.4).

We are to find the scale factor of the dilation and the co-ordinates of the point B''.

From the given graph, we note that

the co-ordinates of point A are (4, 8).

Now, If S is the scale factor of dilation, then we must have

$S\times (4,8)=(3.2,6.4)\\\\\Rightarrow (4S,8S)=(3.2,6.4)\\\\\Rightarrow S=\dfrac{3.2}{4}=\dfrac{6.4}{8}=0.8.$

So, the scale factor is 0.8.

Now, the co-ordinates of point B are (-4, -6). So, the co-ordinates of B'' will be

$(-4\times 0.8,-6\times 0.8)=(-3.2,-4.8).$

Thus, the correct option is

(A) The scale factor is 0.8 and the coordinates of point B" are (–3.2, –4.8).

4 0

4 years ago

Read 2 more answers

Answer this correctly for brainliest pls!!

Molodets [167]

A function that depicts depreciation can be represented as equations, graphs and tables.

<h3>The yearly value of each car for the first five years</h3>

The functions are given as:

$V(t) =C(1 - r^t)$

$V(t) =C(1 - r)^t$

Where:

C = 5895 --- the initial value of the car

r = 22% --- the rate of depreciation

For the first 5 years, the values of t = 1, 2, 3, 4 and 5

For the first function, we have:

$V(1) =5895(1 - 22\%^1) = 4598.1$

$V(2) =5895(1 - 22\%^2) = 5609.7$

$V(3) =5895(1 - 22\%^3) = 5832.2$

$V(4) =5895(1 - 22\%^4) = 5881.2$

$V(5) =5895(1 - 22\%^5) = 5892.0$

For the second function, we have

$V(1) =5895(1 - 22\%)^1 = 4598.1$

$V(2) =5895(1 - 22\%)^2 = 3586.5$

$V(3) =5895(1 - 22\%)^3 = 2797.5$

$V(4) =5895(1 - 22\%)^4 =2182.0$

$V(5) =5895(1 - 22\%)^5 = 1702.0$

So, the table of values is:

$\left[\begin{array}{ccc}Years&Car\ 1&Car\ 2\\1&4598.1&4598.1\\2&5609.7&3586.5\\3&5832.2&2797.5\\4&5881.2&2182.0\\5&5892.0&1702.0\end{array}\right]$

See attachment for the graphs of the two functions

<h3>Interpreting the graphs</h3>

The graph of car 1 increases up to C(t) = 5895, and then remains constant as the value of t increases while the graph of car 2 follows an exponential pattern.

This means that, the graph 2 that follows an exponential pattern is more realistic

<h3>The worth of the cars after 5 years</h3>

From the table, the worth of car 1 is $5892.0, while the worth of car 1 is $1702.0

Read more about graphs and functions at:

brainly.com/question/13473114