Answer:
The correct answer is - through facilitated diffusion and active transport.
Explanation:
Glucose is a six-carbon sugar molecule that is directly utilized by cells to provide energy. A glucose molecule is large enough to go through a cell membrane with simple diffusion.
Cells help glucose molecules to cross the cell membrane through facilitated diffusion and active transport. Active transport is of two types primary and secondary active transport to help the glucose molecule to cross the membrane.
Thus, the correct answer is - through facilitated diffusion and active transport.
Answer:DNA has three types of chemical component: phosphate, a sugar called deoxyribose, and four nitrogenous bases—adenine, guanine, cytosine, and thymine. Two of the bases, adenine and guanine, have a double-ring structure characteristic of a type of chemical called a purine.
Explanation:
Answer:
The correct answer is explained below:
Explanation:
- According to the question, heterozygous tall, heterozygous axillary plant has the following genotype, TtAa.
- It produces the following gametes: TA, Ta, tA, ta.
- The heterozygous tall, terminal plant has the following genotype: Ttaa
- It produces the following gametes: Ta, ta.
- Crossing them,
TA Ta tA ta
Ta TTAa TTaa TtAa Ttaa
(Tall, Axillary) (Tall, Terminal) (Tall, Axillary) (Tall, Terminal)
ta TtAa Ttaa ttAa ttaa
(Tall, Axillary) (Tall, Terminal) (Short, Axillary) (Short, Terminal)
- The genotypes of the offspring obtained are: TTAa, TTaa, TtAa, Ttaa, ttAa and ttaa respectively.
- The phenotypes obtained are:
- Tall, Axillary = 3.
- Tall, Terminal = 3.
- Short, Axillary = 1.
- Short, Terminal = 1.
