Question

If a rock is dropped with a weight of 50kg and friction due to air resistance produces a force of 98N, what is the net force in the Y direction?
PLEASE HELP 11 POINTS

Answer 1

Answer:

The net force is 392N, pointing down.

Explanation:

The net force is the sum of all forces acting on the rock, namely the gravity ("+" acting downward) and the friction force due to air resistance ("-" acting upward):

$F_{net} = F_g - F_{air}\\F_{net} = m\cdot g - F_{air} = 50kg\cdot 9.8\frac{m}{s^2}-98N= (490-98)N=392N$

The net force is 392N and pointing down (positive)/