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olga nikolaevna [1]
3 years ago
7

If a person walks 1km north , 5 km West , 3km south and 7km east, find the resultant displacement vector

Physics
1 answer:
raketka [301]3 years ago
3 0

Y = +1-3 = -2  

X = -5+7 = +2  

D = √2^2-2^2 = 2√1+1 = 2√2 km

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A body accelerates uniformly from rest at 2m/s square. calculate it's velocity after traveling 9m.​
Talja [164]

Answer:

6m/s

Explanation:

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Initial velocity  = 0m/s

Acceleration  = 2m/s²

Distance  = 9m

Unknown:

Final velocity = ?

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To solve this problem, we use the expression below:

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u is the initial velocity

a is the acceleration

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3 0
3 years ago
A 5kg ball is on top of the school building at a height of 40m above the ground.
mojhsa [17]

Answer:

A-Caclcuate the potential energy of the ball at that height

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(b). Now, By the law of the conservation of the Energy, Total amount of the energy of the system remains constant.

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∴ Kinetic Energy = 980 J.

(c). Kinetic Energy = 980 J.

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∴ 980 = 1/2 × 10 × v²

∴ v² = 980/5

⇒ v² = 196

∴ v = 14 m/s.

3 0
2 years ago
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