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nataly862011 [7]
3 years ago
6

Hang two sheets of paper vertically from adjacent corners. The sheets should be parallel and close to each other with a small ga

p between them. Now gently blow down between the two sheets. What happens?
Physics
1 answer:
Liula [17]3 years ago
7 0

Answer:

The sheets move toward each other and the gap narrows                      

Explanation:

          When two sheets are arranged or hanged in such a way, there is a small gap in between the two parallelly hanging sheets. This gap is filled by the surrounding air.

          Now if we blow gently in between the gap of the two sheets, we will observe that the two sheets move towards each other and will come closer thereby narrowing the gap in between them.  

          This is because as we blow through the gap, partial vacuum is created in between the sheet for a short time. So this vacuum is filled by the air surrounding the two sheets thereby forcing the two sheets closer.

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Any four difference between velocity and acceleration​
pychu [463]

Answer:

https://physicsabout.com/acceleration-and-velcoity/

7 0
3 years ago
Modern wind turbines generate electricity from wind power. The large, massive blades have a large moment of inertia and carry a
ANTONII [103]

Answer:

Explanation:

a )

Each blade is in the form of rod with axis near one end of the rod

Moment of inertia of one blade

= 1/3 x m l²

where m is mass of the blade

l is length of each blade.

Total moment of moment of 3 blades

= 3 x\frac{1}{3}  x m l²

ml²

2 )

Given

m = 5500 kg

l = 45 m

Putting these values we get

moment of inertia of one blade

= 1/3 x 5500 x 45 x 45

= 37.125 x 10⁵ kg.m²

Moment of inertia of 3 blades

= 3 x 37.125 x 10⁵ kg.m²

= 111 .375 x 10⁵ kg.m²

c )

Angular momentum

= I x ω

I is moment of inertia of turbine

ω is angular velocity

ω = 2π f

f is frequency of rotation of blade

d )

I = 111 .375 x 10⁵ kg.m² ( Calculated )

f = 11 rpm ( revolution per minute )

= 11 / 60 revolution per second

ω = 2π f

=  2π  x  11 / 60 rad / s

Angular momentum

= I x ω

111 .375 x 10⁵ kg.m² x  2π  x  11 / 60 rad / s

= 128.23 x 10⁵  kgm² s⁻¹ .

4 0
3 years ago
The total amount of kinetic energy and potential energy within a system is called Question 4 options: A. thermal energy B.electr
dolphi86 [110]
I'm pretty sure the answer is C. :)
5 0
3 years ago
determine the pressure exerted on the surface of a submarine cruising 175 ft below the free surface of the sea. assume that the
Alenkasestr [34]

Answer:

92.81 psia.

Explanation:

The density of water by multiplying its specific gravity by the density of sea water.

SG = density of sea water/density of water

ρ = SG x ρw

1 kg/m3 = 62.4 lbm/ft^3

= 1.03 * 62.4

= 64.27lbm/ft^3.

The absolute pressure at 175 ft below sea level as this is the location of the submarine.

P = Patm +ρgh

= 14.7 + 64.27 * 32.2 * 175

Converting to pound force square inch,

= 14.7 + 64.27 * (32.2ft/s^2) * (175ft) * (1lbf/32.2lbm⋅ft/s^2) * (1ft^2/144in^2 )

= 14.7 + 78.11 psia

= 92.81 psia.

8 0
3 years ago
What was significant about the discovery of gallium
Kryger [21]
It confirmed medeleeve's hypothesis (prediction) and showed the use of his table
8 0
3 years ago
Read 2 more answers
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