Answer:
Explanation:
The charge on 10μF capacitor = 10 x 12 x 10⁻⁶ = 120 μC
when it is connected with 20μF capacitor both acquires common potential whose value is
= 120 x 10⁻⁶ /( 10 +20) x 10⁻⁶ = 4 V.
Energy stored in 20μF capacitor =1/2 x 20 x 10⁻⁶ x 4 x 4 = 160 x 10⁻⁶ J.
Answer: young's modulus
Explanation: A very rigid material—one that stretches or compresses only slightly under large forces—has a large value of young's modulus .
To find average speed, we can use the formula:
speed(m/s) = total distance (m) / time (s)
total distance = 4km + 3km = 7km = 7000m
time = 1.5 hours = 5400s
speed = 7000/5400 = 1.30m/s
To find average velocity, we can use the same formula, but replacing total distance with total displacement.
total displacement = 5km = 5000m (if we use the distance to Sheila's house and the distance from her house to the supermarket as the vector arrows for vector addition, we get 5km, as stated in the question)
velocity = 5000/5400 = 0.926m/s
Because this is a velocity, we need the direction. To find this we can use the formula:
tan (theta) = opposite / adjacent
tan (theta) = 3000/4000
sin(tan (theta))^-1 = sin (3000/4000)^-1
theta = 48.6° East of North or 41.4° North of East
So the average velocity is 0.926m/s [48.6° East of North/ 41.4° North of East]
Answer:
The student needs to group variables into dimensionless quantities.
Explanation:
Large experiments take a lot of time to perform because the significant variables need to be separated from the non-significant variables. However, for large quantities of variables, it is necessary to focus on the key variables.
One technique to do that is to use the Buckingham Pi Theorem. The theorem states that the physical variables can be expressed in terms or independent fundamental physical quantities. In other words:
P = n- k
n = total number of quantities
k = independent physical quantities.
A place to start with will be to find dimensionless quantities involving the mass, length, time, and at times temperature. These units are given as M, L, T, and Θ
The grouping helps because it eliminates unwanted and unnecessary experiments.
