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artcher [175]
3 years ago
6

Identify the mathematical proportion that relates electrostatic force and displacement for a pair of charged particles.

Physics
1 answer:
sesenic [268]3 years ago
4 0

Answer:

D. Inverse square

Explanation:

According to the information you are giving me, you must be referring to Coulomb's law because the electrostatic force in proportion to the displacement of charged particles is F =\frac{kq_{1}q_{2}}{r²}.

As you can see, there is a reason as to why this is also referred to as Coulomb's inverse square law because the r² represents the displacement or distance relative to the position of the particles which is squared, and it is inverse because the force and the product of the distance squared is equal to the product of the two charges particles multiplied by coulomb's constant (k) which is approximately 8.9875517923×10⁹ kg⋅m³⋅s⁻²⋅C⁻².

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A constant force moves an object along the line segment from to . Find the work done if the distance is measured in meters and t
vladimir2022 [97]

This question is incomplete, the complete question is;

Flag

A constant force F = 6i+8j-6k moves an object along a straight line from point (6, 0, -10) to point (-6, 7, 2).

Find the work done if the distance is measured in meters and the magnitude of the force is measured in newtons.

Answer:

the work done is -88 J

Explanation:

Given the data in the question;

we know that;

Work done = F × S

where constant force F = ( 6i + 8j - 6k )

S = ( -6i + 7j + 2k ) - ( 6i + 0j - 10k )

S = ( (-6i - 6i) + (7j - 0j) + ( 2k - ( -10k) ) )

S = ( -12I + 7j + 12k )

so

Work force = ( 6i + 8j - 6k ) × ( -12I + 7j + 12k )

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Work force = -72 + 56 - 72

Work force = -88 J

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