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Zina [86]
3 years ago
9

A 878-kg (1940 lb) dragster, starting from rest, attains a speed of 25.9 m/s (57.9 mph) in 0.62 s. (a) Find the average accelera

tion of the dragster during this time interval?
Physics
1 answer:
salantis [7]3 years ago
7 0

Answer:

41.8m/s^2

Explanation:

Since the dragster starts from rest, initial velocity (u) = 0m/s, final velocity (v) = 25.9m/s, time (t) = 0.62s

From the equations of motion, v = u + at

a = (v - u)/t = (25.9 - 0)/0.62 = 25.9/0.62 = 41.8m/s^2

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The blackbody emission spectrum of object A peaks in the ultraviolet region of the electromagnetic spectrum at a wavelength of 2
seraphim [82]

Answer:

A) Object A is 3.25 times hotter.

B) Object A radiates 111.6 times more energy per unit of area.

Explanation:

Wiens's law states that there is an inverse relationship between the wavelength in which there is a peak in the emission of a black body and its temperature, mathematically,

\lambda_{peak}= \dfrac{0.0028976}{T},

where T is the temperature in kelvins and, \lambda_{peak} is the wavelenght (in meters) where the emission is in its peak.

From here, if we solve Wien's law for the temperature we get

T=\dfrac{0.0028976}{\lambda_{peak}}.

Now, we can easily compute the temperatures.

For object A:

T_{A}=\dfrac{0.0028976}{200*10^{-9}}

T_{A}=14488K.

For object B:

T_{B}=\dfrac{0.0028976}{650*10^{-9}}

T_{B}=4458K

From this, we get that

T_{A}/T_{B}=3.25,

which means that object A is 3.25 times hotter.

Stefan's Law states that a black body emits thermal radiation with power proportional to the fourth power of its temperature.

This is

E=\sigma T^{4},

where  \sigma=5.67*10^{-8}\ Wm^{-2}K^{-4} is call the Stefan-Boltzmann constant.

From this, power can be easily compute:

E_{A}=(5.67*10^{-8}*(14488)^{4})=2.5*10^{9}W\\E_{B}=(5.67*10^{-8}*(4458)^{4})=22.4*10^{6}}W,

and we can notice that

E_{A}/E_{B}=111.6,

which means that object A radiates 111.6 time more energy per unit of area.

8 0
3 years ago
Which vector is the sum of the vectors shown below?
Vinil7 [7]
The answer is going to be C
5 0
3 years ago
The gravitational force between two objects is 2400 N. What will be the gravitational force between the objects if the mass of o
Sindrei [870]

Answer:

4800N

Explanation:

F=GmM/r^2

F=infinite m

F=2F

=2(2400N)

=4800N

7 0
3 years ago
A fin whale is swimming at the speed of 35 km/h how many hours will it take to swim 7 km
Aleks04 [339]

Answer:

0.2 hours

Explanation:

\frac{7}{35}  = 0.2

7 0
2 years ago
After fertilization in the fallopian tube, how many days will the zygote travel before arriving at uterus?.
natta225 [31]

After fertilization in the fallopian tube, It will take 6-12 days for the zygote to travel before arriving at the uterus.

<h3>What is a zygote?</h3>

A zygote is, generally speaking, a cell created by the fusion of two gametes; the growing person is created from such a cell.

It takes the zygote around 6–12 days following fertilization in the fallopian tube for the fertilized egg to travel to the uterus and attach to the uterus, a process known as implantation.

Hence It will take 6-12 days for the zygote to travel before arriving at the uterus.

To learn more about the zygote refer;

brainly.com/question/465851

#SPJ1

6 0
2 years ago
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