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2 years ago

Find the amount of simple interest on a loan of $2,500 at 4.44% interest for 12.75 months. (Round to the nearest cent)

Mathematics

1 answer:

masya89 [10]2 years ago

3 0

Standard pay in monthl 196 + 111 = 217
2500* 4.44 / 100 = 111 iterest per month

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Of the pets in the pet show, 10/12 are cats. 6/10 of the cats are calico cats. What fraction of the cats are calico cats?

Lera25 [3.4K]

Answer:

6/10, simplified 3/5

Step-by-step explanation:

kinda tricky, but the fraction is stated right out.

8 0

3 years ago

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(X^3-9x-7) divided by (x-10)

Lera25 [3.4K]

Do you just need to simplify?

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3 years ago

find the equation of the line passes through the point (-1,2) and making an angle of 45° with the line x-y+1=0

Vlad1618 [11]

Answer:

Step-by-step explanation:

line given is x-y+1= 0

you can rewrite it in slope intercept y=mx+b where m is the slope, and b is the y-intercept where the line meets the y-axis

x-y+1 =0 subtract x and 1 from both sides of the equation

-y = -x-1 multiply both sides by -1

y = x+1 so the slope of this line is 1 and the y-intercept is 1

If you draw this line you can see that there are actually 2 lines that form 45° angles with y=x+1 and pass through (-1, 2), one is vertical x= -1 and one horizontal y =2

8 0

3 years ago

CAN ANYONE HELP ME PLZ>>> find the distance-round to the nearest 10nth if necessary

nekit [7.7K]

Answer:

7.3

Step-by-step explanation:

You have to make this a pythagorean theorm equation.

so you would have a side length of 7 and 2.

7^2+2^2=c^2

49 + 4 = c^2

53 = c^2

sqrt:53

7.28010

round

7.3

4 0

3 years ago

L1 and L2 are two straight lines. The origin of the coordinate axes is O. L1 has equation 5x + 10y = 8 L2 is perpendicular to L1

Ivenika [448]

Answer:

40 sq units

Step-by-step explanation:

$5x + 10y = 8\\\Rightarrow y=\dfrac{8-5x}{10}\\\Rightarrow y=-\dfrac{1}{2}x+\dfrac{2}{5}$

Slope of $L_2$ is $m_2$

$m_1m_2=-1\\\Rightarrow m_2=-\dfrac{1}{m_1}\\\Rightarrow m_2=-\dfrac{1}{-\dfrac{1}{2}}\\\Rightarrow m_2=2$

$L_2$ passes through point $(8,6)$

$y-6=2(x-8)\\\Rightarrow y=2x-16+6\\\Rightarrow y=2x-10$

Point at x axis where $L_2$ intersects is

$0=2x-10\\\Rightarrow x=\dfrac{10}{2}\\\Rightarrow x=5$

Point $A$ of the triangle will be $(5,0)$

$L_2$ intersects line $x=-3$ . The point is

$y=2\times(-3)-10\\\Rightarrow y=-6-10\\\Rightarrow y=-16$

The points of the triangle are $A(5,0), O(0,0), B(-3,-16)$

Area of triangle is given by

$A=\dfrac{|A_x(B_y-O_y)+B_x(A_y-O_y)+O_x(A_y-B_y)|}{2}\\\Rightarrow A=\dfrac{|5(-16-0)+-3(0-0)+0(0-(-16))|}{2}\\\Rightarrow A=40\ \text{sq units}$

The area of the triangle is 40 sq units.

6 0

3 years ago