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3 years ago

7. Which two substances do geologists use in radiocarbon dating?

Chemistry

1 answer:

Sav [38]3 years ago

7 0

Carbon -14 and Carbon 12 are the two substances geologists use in radiocarbon dating.

Answer: Option B

Explanation:

Radiocarbon dating denotes the determination process of the age of fossils of plants or animals based on the ratio of carbon atoms 14 to 12. Carbon naturally exists in two non-radioactive isotopes, Carbon-12 and Carbon-13 and one radioactive isotope carbon 14. The carbon 14 gets released on continuous cosmic reaction with atmospheric nitrogen.

These carbon 14 will be absorbed by the living plants and from the plants. Then, it will enter inside the animals which consume the plants. But once the plants and animals died, they ceased to intake carbon-14. In their living state, the ratios of carbon atoms 14 to 12 in them tends to similar to the ratio in atmosphere.

But after they die, the ratio of C-14 to C-12 will be varying from the ratio of C-14 to C-12 in atmosphere as the concentration of C-14 will be decreasing in the dead animals and plants. Thus using this ratio, geologists can find the fossil's age.

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Can someone please describe what they’re seeing in this picture?

Oduvanchick [21]

Answer:

In the given figure, There are two atoms -

Sodium ( Na )
Chlorine ( Cl )

sodium has one electron in valence shell and to get noble gas configuration ( stability ) it need to donate the outer most electron.

whereas,

chlorine has 7 electrons in valence shell and to get noble gas configuration ( stability ) it need to get one more electron.

in this condition Na ( sodium ) donates it's outermost electron to Cl ( chlorine ) and both became stable.

but now sodium has more number of protons than the electrons hence it get positive (+) charge and chlorine has more electrons than the protons hence it get negative (-) charge

so, they get stick to each other by strong electrostatic force acting on the charged atoms and forms a salt " NaCl " ( sodium chloride ) .

i hope it helped you.....

5 0

2 years ago

The density of titanium is 4.51 g/cm^3. what is the volume (in cubic inches) of 3.5 lb of titanium?

Lina20 [59]

(3.5 lb Ti) x (453.592 g Ti / 1 lb Ti) x (1 cm^3 Ti / 4.51 g Ti) x 0.0610237 in^3 / 1 cm^3) = 21 in^3 Ti. Use factor label method to cancel out units and make sure to cancel out the units to the solution, which in this case is volume of titanium in cubic inches. We only keep two digits because the original numbers use have two sig figs as the least amount when doing multiplication or division.

4 0

2 years ago

Read 2 more answers

Molecular chlorine and molecular fluorine combine to form a gaseous product. Under the same conditions of temperature and pressu

uranmaximum [27]

Answer:

Cl F₃

Explanation:

1) Reactants:

The reactants are:

Molecular chlorine: this is a gas diatomic molecule, i.e. Cl₂ (g)

Molecular fluorine: this is also a gas diatomic molecule: F₂ (g)

2) Stoichiometric coefficients:

One volume of Cl₂ react with three volumes of F₂ means that the reaction is represented with coefficients 1 for Cl₂ and 3 for F₂. So, the reactant side of the chemical equation is:

Cl₂ (g) + 3F₂ (g) →

3) Product:

It is said that the reaction yields two volumes of a gaseous product; then, a mass balance indicates that the two volumes must contain 2 parts of Cl and 6 parts of F. So, one volume must contain 1 part of Cl and 3 parts of F. That is easy to see in the complete chemical equation:

Cl₂ (g) + 3F₂ (g) → 2Cl F₃ (g)

As you see, that last equation si balanced: 2 atoms of Cl and 6 atoms of F on each side, and you conclude that the formula of the product is ClF₃.

8 0

3 years ago

Citric acid (C6H8O7) is a triprotic acid (It has 3 protons that can dissociate when dissolved) found naturally in lemon juice, a

Gnesinka [82]

Answer: The molarity of citric acid that is commercially available lemon juice is 0.416 M

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $C_6H_8O_7$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=3\\M_1=?M\\V_1=20.00mL\\n_2=1\\M_2=1.751M\\V_2=14.26mL$

Putting values in above equation, we get:

$3\times M_1\times 20.00=1\times 1.751\times 14.26\\\\M_1=\frac{1\times 1.751\times 14.26}{3\times 20.00}=0.416M$

Hence, the molarity of citric acid that is commercially available lemon juice is 0.416 M

4 0

2 years ago

Which statement best describes the energy of activation?

Furkat [3]

activation energy start off chemical reaction

6 0

3 years ago

Read 2 more answers