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Virty [35]
2 years ago
15

Can someone help me with my chemistry on my page/account?

Chemistry
1 answer:
lesantik [10]2 years ago
7 0

Answer:

Yes

Explanation:

Text me on here

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Calculate the heat (in J) required to raise the temperature of 3.02 g of solid silver from 22.3 degrees Celsius so solid silver
Furkat [3]

Answer: 17.9 joules

Explanation:

The quantity of Heat Energy (Q) required to heat solid silver depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that,

Q = ?

Mass= 3.02g

C = 0.24J/g°C

Φ = (Final temperature - Initial temperature)

= 47°C - 22.3°C = 24.7°C

Then, Q = MCΦ

Q = 3.02g x 0.240J/g°C x 24.7°C

Q = 17.9 Joules

Thus, 17.9 joules of heat isrequired.

7 0
3 years ago
Anthracite is so hard and pure it is also referred to as a _____.
Serga [27]
<span>Anthracite is also referred to as hard coal because it is so hard and pure. It is very hard and highly compacted with variety of coal that has submetallic luster. It has highest carbon content, the lowest impurities, and highest density of energy of all the coal deposits.</span>
6 0
3 years ago
Which conclusion could be made from Ernest Rutherford’s gold foil experiment?
boyakko [2]

The conclusion was that there must be space between the particles of an atom. The way he knew this is because while some of the radiation reflected off of the gold foil, other radiation went right through it.

5 0
3 years ago
Read 2 more answers
A solution is 40.00% by volume benzene (C6H6) in carbon tetrachloride at 20°C. The vapor pressure of pure benzene at this temper
finlep [7]

Answer:

The total vapor pressure is 84.29 mmHg

Explanation:

Step 1:  Data given

Solution = 40.00 (v/v) % benzene in CCl4

Temperature = 20.00 °C

The vapor pressure of pure benzene at 20.00 °C = 74.61 mmHg

Density of benzene is 0.87865 g/cm3

The vapor pressure of pure carbon tetrachloride is 91.32 mmHg

We suppose the total volume = 100 mL

Step 2: Calculate volume benzene and CCl4

40 % benzene = 40 mL

60 % mL CCl4 = 60 mL

Step 3: Calculate mass benzene

Mass = density * volume

Mass of benzene = 40.00 mL *  0.87865 g/mL = 35.146 g

Step 4: Calculate moles of benzene

Moles = mass / molar mass

Number of moles of benzene  = 35.146 grams / 78 g/mol  = 0.45059 mol

Step 5: Calculate mass of CCl4

Mass of CCl4 = 60 mL * 1.5940 g/mL = 95.64 g

Step 6: Calculate moles CCl4

Number of moles of CCl4 = 95.64 grams / 154g/mol = 0.62104 mol

Step 7: Calculate total number of moles

Total number of moles = moles benzene + moles CCl4

0.45059 moles + 0.62104 moles = 1.07163 mol

Step 8: Calculate mole fraction benzene and CCl4

Mole fraction = moles benzene / total moles

Mole fraction of benzene = 0.45059 / 1.07163 = 0.4205

Mole fraction of CCl4 = 0.62104 / 1.07163 = 0.5795

Step 9: Calculate partial pressure

Partial pressure of benzene = 0.4205 * 74.61 = 31.37 mmHg

Partial pressure of CCl4      = 0.5795 * 91.32 = 52.92 mmHg

Total vapor pressure = 31.37 + 52.92 = 84.29 mmHg

The total vapor pressure is 84.29 mmHg

7 0
2 years ago
Consider the following mechanism: O3 =&gt; O2 + O NO + O =&gt; NO2 What is the role of O2? A. intermediate B. catalyst C. reacta
Daniel [21]

Answer:

The correct answer is option D.

Explanation:

Step 1: O_3\rightarrow O_2+O

Step 2: NO+O\rightarrow NO_2

Overall reaction can be determined  by adding all the reactions of mechanism:

O_3+NO\rightarrow O_2+NO_2

Reactants in an overall reaction = O_3\& NO

Products in an overall reaction = O_2\& NO_2

According to question , the role of oxygen gas is product.

5 0
3 years ago
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