No solution of the system of equations y = -2x + 5 and -5y = 10x + 20 ⇒ 2nd answer
Step-by-step explanation:
Let us revise the types of solutions of a system of linear equations
- One solution
- No solution when the coefficients of x and y in the two equations are equal and the numerical terms are different
- Infinitely many solutions when the coefficients of x , y and the numerical terms are equal in the two equations
∵ y = -2x + 5
- Add 2x to both sides
∴ 2x + y = 5 ⇒ (1)
∵ -5y = 10x + 20
- Subtract 10x from both sides
∴ -10x - 5y = 20
- Divide both sides by -5
∴ 2x + y = -4 ⇒ (2)
∵ The coefficient of x in equation (1) is 2
∵ The coefficient of x in equation (2) is 2
∴ The coefficients of x in the two equations are equal
∵ The coefficient of y in equation (1) is 1
∵ The coefficient of y in equation (2) is 1
∴ The coefficients of y in the two equations are equal
∵ The numerical term in equation (1) is 5
∵ The numerical term in equation (2) is -4
∴ The numerical terms are different
From the 2nd rule above
∴ No solution of the system of equations
No solution of the system of equations y = -2x + 5 and -5y = 10x + 20
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6a+12=2(3a-8)
6a+12=6a-16
-12. -12
6a=6a-4
-6a -6a
0=-4
no solution because the equation is false.
Answer:
112.5
Step-by-step explanation:
200 - 87.5 = 112.5
Answer:
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Step-by-step explanation:
v mkkjljjj
Judging by the problem you want me to use substitute method
Since why equals 1/2x-1 you
Do 2(1/2x-1)= x-2
You multiple by 2 cause there’s two on the top for y. So the problem is now 4x-x-2
Combine like terms 3x+2=14
Subtract two on both sides
3x=12
X=4
Go back to the bottom since u know x now do y= 4.1/2-1 solve to get one
Y=1 so your answer is (4,1)