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2 years ago

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If the standard deviation of an exam is 5, the z-score us 1.95 and the mean is 80; what is the actual test score? (Round the ans

wer to the nearest hundredth)

1 answer:

skad [1K]2 years ago

6 0

If the standard deviation of an exam is 5, the z-score us 1.95 and the mean is 80, the actual test score is; 89.75

<h3>How to solve z-score problems?</h3>

We are given;

Standard deviation; s = 5

z-score = 1.95

Mean = 80

Formula for z-score is;

z = (x' - μ)/σ

Thus;

1.95 = (x' - 80)/5

1.95 * 5 = (x' - 80)

9.75 = x' - 80

x' = 80 + 9.75

x' = 89.75

Read more about Z-score Problems at; brainly.com/question/25638875

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$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

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$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

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Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

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