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maxonik [38]
3 years ago
13

8x+23/(x+3)(x+2) partial fraction decomposition

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
6 0

Answer:

1/(x+3)+7/(x+2)

Step-by-step explanation:

I'm assuming the full numerator is (8x+23)... and by making that assumption I'm assumed the fraction was (8x+23)/[(x+3)(x+2)].

(8x+23)/[(x+3)(x+2)]=A/(x+3)+B/(x+2)

8x+23=A(x+2)+B(x+3)                   I multiply both sides by (x+3)(x+2)

Set x to -2 that gives -16+23=B          so this means B=7

Set x to -3 instead that gives -24+23=A(-1)   so this means A=1

So (8x+23)/[(x+3)(x+2)]=1/(x+3)+7/(x+2)

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BaLLatris [955]
For this case, what we must do is find the distance between each ordered pair.
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 For (0, 0) and (0, 7):
 
d1=\sqrt{(0-0)^2+(7-0)^2}
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 For (0, 7) and (5, 7):
 
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d3=\sqrt{(5-5)^2+(7-0)^2}
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 Answer:
 
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5 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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Hopefully i understood the question correctly :) Hope this helps
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How do you solve this equation?
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Step-by-step explanation:

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