Question

Titanium metal requires a photon with a minimum energy of 6.94×10^−19J to emit electrons.

Answer 1

Answer:

(a) Frequency will be $1.05\times 10^{15}Hz$

(b) Wavelength will be $2.857\times 10^{-7}m$

Explanation:

We have given that energy of a photon is $E=6.94\times 10^{-19}j$

Plank's constant $=6.6\times 10^{-14}js$

(a) We know that energy of photon is given by

$E=h\nu$

So $6.94\times 10^{-34}=6.6\times 10^{-34}\times \nu$

$\nu =1.05\times 10^{15}Hz$

(b)We know that wavelength of photon is given by

$\lambda =\frac{c}{f}=\frac{3\times 10^8}{1.05\times 10^{15}}=2.857\times 10^{-7}m$