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3 years ago

7

Metallic bonding generally occurs between

1 answer:

blsea [12.9K]3 years ago

8 0

Metallic bondings occurs between metals (the metals delocalize their valance electrons and the attraction occurs between the now positive metals and the de localized sea of electrons)

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Two cars have identical horns, each emitting a frequency of fs = 406 Hz. One of the cars is moving with a speed of 10.5 m/s towa

Archy [21]

Answer:

$f_{B}=12.8 Hz$

Explanation:

Let's start finding the frequency heard by the bystander due to the moving car. We need to use Doppler effect here:

$f_{obs}=f_{s}\left(\frac{v}{v-v_{car}}\right)$

v is the speed of sound (v = 343 m/s)

So, we have:

$f_{obs}=406\left(\frac{343}{343-10.5}\right)=418.8 Hz$

Now, the beat frequency heard by the bystander is the combine of the frequencies, it means the difference between them. Therefore the equation is given by:

$f_{B}=f_{obs}-f_{s}=418.8-406=12.8 Hz$

I hope it helps you!

4 0

3 years ago

(b) The density of aluminum is 2.70 g/cm3. The thickness of a rectangular sheet of aluminum foil varies

vekshin1

Answer:

(i) $22.48 cm^3$

(ii) $1.5 mm$

Explanation:

Let t be the average thickness of the sheet.

Given that:

Density of the aluminum sheet is $2.70 g/cm^3$

Mass of sheet = 60.7 g

Length of sheet = 50.0 cm

Width of sheet = 30.0 cm

(i) Using, Density=Mass/Volume

$\Rightarrow \text{Volume}=\frac{\text{Mass}}{\text{Density}}$

$\Rightarrow \text{Volume}=\frac{60.7}{2.7}=22.48 cm^3$

Hence, the volume of the sheet is $22.48 cm^3$ .

(ii) Now, as this aluminum sheet is in the shape of a cuboid, so the volume of the sheet is

$\text{Volume}=\text{Length}\times\text{Width}\times\text{Thickness}$

$\Rightarrow 22.48=50\times 30 \times w$

$\Rightarrow w=\frac{22.48}{50\times 30}=0.015 cm$

Hence, the average thickness of the sheet is $1.5 mm$ .

6 0

3 years ago

Which subatomic particle is NOT found in the nucleus of an atom? *

Vinil7 [7]

Answer:

Electrons

Explanation:

Only Protons and Neutrons are found in the nucleus

3 0

3 years ago

Read 2 more answers

As the shuttle bus comes to a sudden stop to avoid hitting a dog, it accelerates uniformly and at -4.1m/s^2 as it slows from 9.0

Tju [1.3M]

Hope this helps you.

5 0

3 years ago

10. If the gravitational force between two objects of equal mass is found to be 4.60*10^-6 N when the objects are 15 meters apar

liraira [26]

Answer:

Explanation:

F = G*m1 * m2 / r^2

G = 6.67408 × 10-11 m3 kg-1 s-2

r = 15 m

F = 4.60 * 10^-6 N

m1 = m2 = m

F = 6.67 * 10^-11 * m^2 / 15^2

4.60 * 10^-6 = 6.67 * 10^-11 * m^2 / 225 Multiply both sides by 225

4.60*10^-6 * 225 = 6.67*10^-11 * m^2

.001035 = 6.67408 × 10-11 * m^2 Divide by 6.67408 × 10-11

0.001035/ 6.67408 × 10-11 = m^2

m^2 = 15507755 Take the square root of both sides

m = sqrt(15507755 )

m = 3938 kg

5 0

3 years ago