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2 years ago

If the measure of arc AB is 50 degrees, what is the measure of angle ADB?

Mathematics

1 answer:

lubasha [3.4K]2 years ago

3 0

Answer:

25 degrees

Step-by-step explanation:

arc divided by 2 = angle

50/2=25

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Help will name Brainliest

11111nata11111 [884]

Answer:

x = $\frac{\sqrt{22} }{2}$

Step-by-step explanation:

Using the Pythagorean Theorem we can solve this problem.

The legs of the triangle will be the same (the dashes in the middle of the line indicates they are the same).

The Pythagorean Theorem will look like this:

$a^{2}+a^{2} = (\sqrt {11})^{2}$

Now, let's find a:

$2a^{2} = 11$ The square of a radical will be whatever is under the arch

$a^{2}=\frac{11}{2}$ Divide 11 by 2

$\sqrt{a^{2} } = \sqrt{\frac{11}{2} }$ Square root both sides

a = $\frac{\sqrt{22} }{2}$

Therefore, the length of side x is equal to $\frac{\sqrt{22} }{2}$ .

Hope this helps!!

8 0

2 years ago

Please help!!! I really don’t get this only I get where the 3 are but please help me for the 4/5 and -0.4!

Naily [24]

Answer:

-0.4 should be in between 0 and -0.5, however be as close to -0.5 as possible while not being ON -0.5.

3 4/5 should be in between 3 and 4, so you can split 4/5 into 8/10 which are equal to each other. Then you can pretend to split the 3 and 4 gap into 10 equal pieces. After you split the gap, count 8 parts to the left of 3.

Step-by-step explanation:

I hope you understand what I mean.

8 0

3 years ago

Involving the selection of frozen dinners. Assume that there are 15 frozen dinners: 7 pasta, 6 chicken, and 2 seafood dinners. T

zzz [600]

The probability that at least 2 of the dinners selected are pasta dinners will be 0.8181...

<u><em>Explanation</em></u>

Pasta dinners = 7 , Chicken dinners = 6 and Seafood dinners = 2

The student selects 5 of the total 15 dinners. So, total possible ways for selecting 5 dinners $=^1^5C_{5} =3003$

For selecting at least 2 of them as pasta dinners, the student can select 2, 3, 4 and 5 pasta dinners from total 7 pasta dinners.

So, the possible ways for selecting 2 pasta dinners $=^7C_{2}*^8C_{3} =1176$

The possible ways for selecting 3 pasta dinners $=^7C_{3}*^8C_{2} =980$

The possible ways for selecting 4 pasta dinners $=^7C_{4}*^8C_{1} =280$

The possible ways for selecting 5 pasta dinners $=^7C_{5}*^8C_{0} =21$

Thus, the probability for selecting at least 2 pasta dinners $=\frac{1176+980+280+21}{3003} =\frac{2457}{3003} =0.8181.....$

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4 years ago

In division what goes inside the house

AfilCa [17]

So if you have 2/3 then it flips so the top number or numberator is in the house (aka dividend)

5 0

3 years ago

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A population of geese grow in such a way that each generation is simply 2.2 times the previous generation. There were 3 geese in

lapo4ka [179]

First generation: 3

Second generation: $3\times2.2$

Third generation: $3\times2.2\times2.2=3\times2.2^2$

Fourth generation: $3\times2.2\times2.2\times2.2=3\times2.2^3$

And so on. The general formula for the $n$ th generation is $3\times2.2^{n-1}$ . So by the 15th generation, you should expect around $3\times2.2^{15-1}\approx186655$ geese.

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3 years ago

Read 2 more answers