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DIA [1.3K]
2 years ago
7

How to find when,y=-1/3x - 3​

Mathematics
1 answer:
Montano1993 [528]2 years ago
7 0
The -3 would be where your line crosses the y-axis, so you would plot your point at -3. your slope will always be counted as rise/run, basically meaning you would count along the y-axis a certain amount of times, in this case -1, and along the x-axis a certain amount of times, here would be three. your next plot point would be (3,-4) and so on. hope this helped!
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If B is the midpoint of AC, AC=CD, AB=3x+4, AC=11x-17, and CE=49, find DE.
Luba_88 [7]

Answer:

11

Step-by-step explanation:

AB = 3x + 4 and AC which is twice of AB is equal to 11x - 17

2 (3x + 4) = 11x - 17

6x + 8 = 11x - 17

8 + 17 = 11x - 6x

25 = 5x

5 = x

AC = CD = 11x - 17 ➡ 11×5 - 17 = 38

CD = 38 and DE = 49 - 38 = 11

6 0
3 years ago
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OlgaM077 [116]
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1. n - 7
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4 0
3 years ago
Chanasia has 8.75 gallons of paint. She wants to use 2 5 of the paint to paint her living room. How many gallons of paint will C
GaryK [48]

Answer: 3.5 gallons

Step-by-step explanation:

From the question, we are told that Chanasia has 8.75 gallons of paint and that she wants to use 2/5 of the paint to paint her living room.

The gallons of paint that Chanasia will use be gotten by multiplying 2/5 by 8.75 gallons. This will be:

= 2/5 × 8.75 gallons

= 0.4 × 8.75 gallons

= 3.5 gallons.

This means that Chanasia will use 3.5 gallons to paint her living room

7 0
3 years ago
A projectile is fired from ground level with an initial speed of 550 m/sec and an angle of elevation of 30 degrees. Use that the
Nana76 [90]

Answer:

x (max) = 26760 m

y (max)  = 3859  meters

V = 549.5  m/sec

Step-by-step explanation:

Equations to describe the projectile shot movement are:

a(x)  =  0     V(x)  =  V(₀) *cos α                  x  =  V(₀) *cos α  * t

a(y)  = -g     V(y)  =  V(₀) * sin α  - g*t         y  =   V(₀) * sin α *t  - (1/2)*g*t²

a ) What is the range of the projectile.   α  =  30°

then  sin 30° = 1/2     cos  30° = √3 /2   and     tan 30° = 1/√3

x  maximum occurs when in the equation of trajectory  we make  y  = 0

Then

y  =  x*tan α  -  g*x / 2*V(₀)²*cos²  α

x*tan α  =  g*x /  2* V(₀)²*cos²  α

By subtitution

1/√3    =   9.8* x(max)  / 2* (550)²*0.75

(1/√3) * 453750 / 9.8  = x (max)

x (max) = 453750 / 16.95   meters

x (max) = 26760 m

The maximum height is when V(y) = 0

We compute t in that condition

V(y)  =  0  =  V(₀) * sin α - g*t

t  =   V(₀) * sin α / g       ⇒   t  =  550* (1/2) / 9.8

t  =  28.06 sec

Then  h (max)  =   y(max)  =  V(₀) sin α * t  - 1/2 g* t²

y (max)  =  550* (1/2)*28.06 - (1/2)* 9.8 * (28.06)²

y (max)  =  7717  -  3858  

y (max)  = 3859  meters

What is the speed when the projectile hits the ground

V  =  V(x)  + V (y)    and   t  =  2* 28.06         t  =  56.12 sec

mod V  =√ V(x)²  + V(y)²

V(x)  =  V(₀) cos α    =  550 * √3/2

V(x)  = 475.5  m/sec       V(x)²   =  226338 m²/sec²

V(y) =  550*1/2   -  9.8* 56.12     ⇒  V(y) = 275  -  549.98

V(y) =  - 274.98          V(y) ²   =  

V =  √ 226338 + 75614     ⇒  V = 549.5  m/sec

7 0
3 years ago
Factor to write an equivalent expression to 36a−16
Dmitry_Shevchenko [17]

Answer:

4(9a-4)

Step-by-step explanation:

4 0
3 years ago
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