Question

Which function is positive for the entire interval [–3, –2]? On a coordinate plane, a curved line with a minimum value of (0, negative 3) crosses the x-axis at (negative 3, 0) and (3, 0), and crosses the y-axis at (0, negative 3). On a coordinate plane, a curved line with a minimum value of (2, negative 3) crosses the x-axis at (negative 1, 0) and (5, 0), and crosses the y-axis at (0, negative 1.5). On a coordinate plane, a curved line with a minimum value of (2, 4) and a maximum value of (0.5, 6), crosses the x-axis at (negative 1.5, 0) and crosses the y-axis at (0, 5). On a coordinate plane, a curved line with a minimum value of (negative 1.75, negative 3.9) and a maximum value of (0, 2), crosses the x-axis at (negative 2.2, 0), (negative 0.75, 0), and (0.75, 0), and crosses the y-axis at (0, 2).

Answer 1

The function that is positive for the entire interval [–3, –2] is the graph of the function (b)

How to determine the function?

See attachment for the proper representation of the available options

For a function to be positive on the interval [-3,-2];

It means that the y values must be in the positive quadrant from x = -3 to x =-2

From the list of options, we have:

The y values from x = -3 to x =-2 is at the positive quadrant for the second graph i.e. option B

Hence, the function that is positive for the entire interval [–3, –2] is the graph of the function (b)

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