Graduate Management Aptitude Test (GMAT) scores are widely used by graduate schools of business as an entrance requirement. Supp
2 answers:
Answer:
B) 369 and 583.
Step-by-step explanation:
We have been given that in one particular year, the mean score for the GMAT was 476, with a standard deviation of 107. We are asked to find the values which are one standard deviation above and below the mean.
To find the score, which is one standard deviation below mean, we will subtract 107 from 476.
To find the score, which is one standard deviation above mean, we will add 107 to 476.
Therefore, the values 369 and 583 are one standard deviation below and above the mean respectively and option B is the correct choice.
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Answer:
The volume of the cylinder = π r² h
where r is the radius of the cylinder and h is the height of the cylinder.
This is formula is applied for the right cylinder as figure 1 and oblique cylinder as figure2.
<u>The volume of the cylinder of figure 1:</u>
r = 6 and h = 7
volume = π r² h = π * 6² * 7 = 252π units³
<u>The volume of the cylinder of figure 2:</u>
r = 11 and h = 15
volume = π r² h = π * 11² * 15 = 1,815π units³
This can be considered as a very easy Question where you have to find the value of √85 and √86 upto 2 decimal places then we could find it easily.
Let's start!
Value of √85=9.21
Value of √86=9.27
Now it is obvious that 9.25 lies between √85 and √86.
What are rational no.?
Any pair of numbers which is in the form of p/q where p and q are integers and p and q are co-prime is called rational number.
Megan:
x to the one third power =
<span>x to the one twelfth power = </span>
<span>The quantity of x to the one third power, over x to the one twelfth power is:
</span>
<span>
Since </span>
then
Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4
Julie:
x times x to the second times x to the fifth = x * x² * x⁵
<span>The thirty second root of the quantity of x times x to the second times x to the fifth is
</span>![\sqrt[32]{x* x^{2} * x^{5} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B32%5D%7Bx%2A%20x%5E%7B2%7D%20%2A%20x%5E%7B5%7D%20%7D%20)
<span>
Since </span>
Then![\sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }](https://tex.z-dn.net/?f=%5Csqrt%5B32%5D%7Bx%2A%20x%5E%7B2%7D%20%2A%20x%5E%7B5%7D%20%7D%3D%20%5Csqrt%5B32%5D%7B%20x%5E%7B1%2B2%2B5%7D%20%7D%20%3D%5Csqrt%5B32%5D%7B%20x%5E%7B8%7D%20%7D)
Since![\sqrt[n]{x^{m}} = x^{m/n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%5E%7Bm%7D%7D%20%3D%20x%5E%7Bm%2Fn%7D%20%7D%20)
Then![\sqrt[32]{ x^{8} }= x^{8/32} = x^{1/4}](https://tex.z-dn.net/?f=%5Csqrt%5B32%5D%7B%20x%5E%7B8%7D%20%7D%3D%20x%5E%7B8%2F32%7D%20%3D%20x%5E%7B1%2F4%7D%20)
Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.
x to the one third power =
<span>x to the one twelfth power = </span>
<span>The quantity of x to the one third power, over x to the one twelfth power is:
</span>
<span>
Since </span>
then
Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4
Julie:
x times x to the second times x to the fifth = x * x² * x⁵
<span>The thirty second root of the quantity of x times x to the second times x to the fifth is
</span>
<span>
Since </span>
Then
Since
Then
Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.