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german
1 year ago
14

Write the expresion in simplest form (-11/2x+30)-2(-11/4x-5/2)

Mathematics
1 answer:
qwelly [4]1 year ago
4 0

The simplified expression of (-11/2x+30)-2(-11/4x-5/2) is 35

<h3>How to simplify the expression?</h3>

The expression is given as:

(-11/2x+30)-2(-11/4x-5/2)

Expand the bracket

-11/2x + 30 + 11/2x + 5

Collect the like terms

11/2x -11/2x + 30 + 5

Evaluate the like terms

35

Hence, the simplified expression of (-11/2x+30)-2(-11/4x-5/2) is 35

Read more about expressions at:

brainly.com/question/723406

#SPJ1

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7 1/2 divided by 3/4
creativ13 [48]

Answer:

10

Step-by-step explanation:

8 0
3 years ago
An SRS of 350 high school seniors gained an average of x¯=21 points in their second attempt at the SAT Mathematics exam. Assume
Lynna [10]

Answer:

a) 21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

b) ME=2.58\frac{52}{\sqrt{350}}=7.17

c) ME=2.58\frac{52}{\sqrt{100}}=13.42

d) D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Part a

\bar X=21 represent the sample mean  

\mu population mean (variable of interest)  

\sigma=52 represent the population standard deviation  

n=350 represent the sample size  

99% confidence interval  

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58  

Now we have everything in order to replace into formula (1):  

21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

Part b

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{350}}=7.17

Part c

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{100}}=13.42

Part d

As we can see when we reduce the sample size we increase the margin of error so the best option for this case is:

D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

6 0
2 years ago
Please helpppppppppp
bija089 [108]

Answer:

A

Step-by-step explanation:

5 0
2 years ago
Determine the value of y when x=15 if y=6 when x =30
Vladimir79 [104]
6+9=15
y+9=x
x=30
y+9=30
y=21
6 0
3 years ago
Once again assistance is needed. Help!!!!
tatiyna

Answer:

D

Step-by-step explanation:

hope this helps

8 0
2 years ago
Read 2 more answers
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