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2 years ago

This is a new version of the question. Make sure you start new workings.

Mathematics

1 answer:

cestrela7 [59]2 years ago

8 0

Answer:

8.5 cm

Step-by-step explanation:

It was a very easy question if I am wrong so sorry i tried my best to answer this question

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Because bernard has some health issues, he must pay 15% more for life insurance. about how much more annually will a $115,000 10

Sergeu [11.5K]

The amount more annually a $115,000 10-year term insurance at age 35 cost Bernard than someone of the same age without health issues is $24.

<h3>What are insurance premiums?</h3>

The insurance premium is paid as a cost to cover a possible loss that is unseen.

The annual premium rate as a percentage of the value insured a person at age 35 has to pay is 0.14%.

From the given information, we have that the amount a 35-year-old without health issues will pay per $1,000 is $1.40

The amount to be paid for $115,000 is 115 × $1.4 = $161

The amount Bernard pays = 15% more

= 1.15 × $161

= $185.15

Therefore,

The amount more Bernard has to pay = $185.15 - $161

= $24.15 ≈ $24

Learn more about insurance premiums here:

brainly.com/question/3053945

3 0

2 years ago

The Smith family went out to eat at Applebees. The total for their meal was $58.25. If they want to leave a 20%, how much tip sh

Len [333]

Answer:

$11.65

Step-by-step explanation:

20% of 58.25, "of" in math means multiplication. So you multiply it.

To get 20% as a fraction you move the decimal 2 places to the left, and it's .2 or .20 so you get this equation:

.20 * 58.25

So your answer is, $11.65.

To find the total of the bill including the tip it would just be

11.65 + 58.25 = 69.90

4 0

3 years ago

If z=sprt5 -sprt2, then Izl=

ASHA 777 [7]

Answer:

is the answer

because sprt - sprt = 0

then 5-2=3

3 0

4 years ago

2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago

The difference of two numbers is 16 the greater number is five less than four times a small number find the two numbers

Elis [28]

Answer:

The numbers are 23 and 7

Step-by-step explanation:

1. Set up the equations

Let x = the greater number

and y = the smaller number. Then

(1) x - y = 16

4y = 4 times the smaller number and

4y - 5 = 5 less than 4 times the smaller number. Then

(2) x = 4y - 5

You have a system of two equations:

$\begin{cases}(1) & x - y = 16\\(2) & x = 4y - 5\end{cases}$

2. Solve the equations

$\begin{array}{lrcll}(3) & 4y - 5 - y & = & 16 &\text{Substituted (2) into (1)}\\& 3y - 5 & = & 16 &\text{Simplified}\\ & 3y & = & 21 &\text{Added 5 to each side}\\(4) &y & = & \mathbf{7} &\text{Divided each side by 3} \\& x - 7 & = & 16 & \text{Substituted (4) into (1)}\\& x& = & \mathbf{23} & \text{Added 7 to each side}\\\end{array}$

The larger number is 23; the smaller number is 7.

3. Check

$\begin{array}{rclcrcl}23 - 7& = & 16 & \qquad &23&=&4(7) - 5\\16 & = & 16 & \qquad &23& = &28 - 5\\&&& \qquad &23& = &23\\\end{array}$

OK.

3 0

3 years ago