How many grams of CO2 are produced if 2.09 moles of hydrochloric acid are reacted with
1 answer:
Answer:
The molar mass of CO2 = 44.01 g/mol
Explanation:
Start with 2.09 moles of HCl and convert to moles of CO2 For every 2 moles of HCl used, 1 mole of CO2 is formed.
2.09 mol HCl •(1 mol CO2/2 mol HCl) = 1.045 mol CO2
Now convert moles of CO2 to grams using the molar mass.
1.045 mol CO2 • 44.01 g/mol = 45.99 grams CO2
3 significant figures = 46.0 grams CO2
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Taking into account the reaction stoichiometry, 2 moles of CaO are required to react with 2 moles of Ca(OH)₂.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
CaO + H₂O → Ca(OH)₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- CaO: 1 mole
- H₂O: 1 mole
- Ca(OH)₂: 1 mole
The following rule of three can be applied: If by stoichiometric reaction 1 mole of Ca(OH)₂ is produced by 1 mole of CaO, 2 moles of Ca(OH)₂ are produced by how many moles of CaO?
moles of CaO= 2 moles
Finally, 2 moles of CaO are required to react with 2 moles of Ca(OH)₂.
Learn more about the reaction stoichiometry:
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Answer: 9.9 grams
Explanation:
To calculate the moles, we use the equation:
a) moles of
b) moles of
According to stoichiometry :
1 mole of combine with 1 mole of
Thus 0.33 mole of will combine with =
mole of
Thus is the limiting reagent as it limits the formation of product.
As 1 mole of give = 1 mole of
Thus 0.33 moles of give =
of
Mass of
Thus theoretical yield (g) of produced by the reaction is 9.9 grams