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2 years ago

12

Is fluorine a nonmetal or metal?

2 answers:

Ratling [72]2 years ago

6 0

Answer:

Nonmetal...

Explanation:

T^T

telo118 [61]2 years ago

6 0

Answer: its a nonmetal

Explanation: you can look up a group divided periodic table to show the groups of different elements.

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If we add a catalyst to the following equation, CO + H2O + heat CO2 + H2, which way will the equilibrium shift?

Igoryamba

Answer:

No effect.

Explanation:

Hello,

In this case, considering the widely studied Le Chatelier's principle, we can realize that the factors affecting equilibrium are concentration, temperature and pressure and volume if the reaction is in gaseous phase and with non-zero change in the number of moles. In such a way, by adding a catalyst to given reaction will have no effect on the equilibrium direction.

Best regards.

7 0

3 years ago

How can I calculate the mass percent of carbon, nitrogen and oxygen in caffeine, C8H10N4O2.

Ahat [919]

You must first calculate the total weight of 1 mole of the substance. You do this by finding the molar weights on the periodic table of each of the elements in the compound:

$8(12.01g)+10(1.008g)+4(14.007g)+2(15.999g)=96.08g+10.08g+56.028g+31.998g=194.186g$

So now we take the amount of each element that is given in the compound and divide it by the total mass of the compound:

Carbon: 96.08g

$\frac{96.08g}{194.186g}= 0.49478=49.48$

Carbon = 49.48%

Nitrogen: 56.028g

$\frac{56.028g}{194.186g}=0.28853=28.85$

Nitrogen = 28.85%

Oxygen: 31.998g

$\frac{31.998g}{194.186g} =0.16478=16.48$

Oxygen = 16.48%

8 0

3 years ago

Read 2 more answers

7.00 of Compound x with molecular formula C3H4 are burned in a constant-pressure calorimeter containing 35.00kg of water at 25c.

beks73 [17]

Answer:

$\Delta H_{f,C_3H_4}=276.8kJ/mol$

Explanation:

Hello!

In this case, since the equation we use to model the heat exchange into the calorimeter and compute the heat of reaction is:

$\Delta H_{rxn} =- m_wC_w\Delta T$

We plug in the mass of water, temperature change and specific heat to obtain:

$\Delta H_{rxn} =- (35000g)(4.184\frac{J}{g\°C} )(2.316\°C)\\\\\Delta H_{rxn}=-339.16kJ$

Now, this enthalpy of reaction corresponds to the combustion of propyne:

$C_3H_4+4O_2\rightarrow 3CO_2+2H_2O$

Whose enthalpy change involves the enthalpies of formation of propyne, carbon dioxide and water, considering that of propyne is the target:

$\Delta H_{rxn}=3\Delta H_{f,CO_2}+2\Delta H_{f,H_2O}-\Delta H_{f,C_3H_4}$

However, the enthalpy of reaction should be expressed in kJ per moles of C3H4, so we divide by the appropriate moles in 7.00 g of this compound:

$\Delta H_{rxn} =-339.16kJ*\frac{1}{7.00g}*\frac{40.06g}{1mol}=-1940.9kJ/mol$

Now, we solve for the enthalpy of formation of C3H4 as shown below:

$\Delta H_{f,C_3H_4}=3\Delta H_{f,CO_2}+2\Delta H_{f,H_2O}-\Delta H_{rxn}$

So we plug in to obtain (enthalpies of formation of CO2 and H2O are found on NIST data base):

$\Delta H_{f,C_3H_4}=3(-393.5kJ/mol)+2(-241.8kJ/mol)-(-1940.9kJ/mol)\\\\\Delta H_{f,C_3H_4}=276.8kJ/mol$

Best regards!

7 0

3 years ago

Which is the most accurate description of compounds?

Alex787 [66]

The answer has to be D

8 0

3 years ago

Read 2 more answers

How does the electron structure of atoms change when they form chemical bonds

andriy [413]

For ionic bond
The metal atom will lose electrons to form cations and the non metal atom will gain electron.egNaCl

3 0

3 years ago