**Answer:**

B and C

**Explanation:**

The different types of motor nerves transmit information to and from muscles, and they connect to muscle fibers through the motor endplate.

**Answer:**

True statements are 2, 4, 5

**Explanation:**

They can be broken down by chemical means because we need to break chemical bonds between two (or more) atoms.

They are pure substance because one can't separate them by physical means.

When one separate compounds on two (or more) substances, there are two (or more) different species and they all act differently.

The data **indicates **a direct **relationship **with a **positive slope**.

<h3>What is direct relationship?</h3>

Direct **relationship **is a type of **relation **in which if one factor **increases **the other will also **increases **and vice versa. This data **represents **direct **relationship **because the **increase **occur in one value **causes **increase of another value so we can conclude that the data **indicates **a direct **relationship **with a **positive slope**.

Learn more about **relationship **here: brainly.com/question/25862883

The value of **ΔG****°**** **(gibbs** **free energy change) is** **-2703kj** **and -2657kj.

Given ,

**combustion** reaction of **butane** :

C4H10(g) + 13/2O2 (g) →4CO2(g) + 5H2O(g)

Method-1 :

We know ,

ΔGrxn = sum of ΔG (product ) - sum of ΔG (reactant )

= [4 × (-394.4) + 5×(-228.6) ] - [1×(-16.7)]

**ΔGrxn = -2720.6kj**

Method-2 :

We know ,

ΔG = ΔH -TΔS

T =298K

Thus , ΔHrxn = sum of ΔH (product ) - sum of ΔH (reactant )

= [4×(-393.5) + 5×(-241.8) ] - [ 1×(-126)]

**ΔHrxn = -2657kj **

ΔSrxn = sum of ΔS (product ) - sum of ΔS( reactant )

= [ 4×(213.7) + 5×188.7 ] - [ 13/2 ×205 + 1×310 ]

ΔSrxn = 155.8j/K

**ΔSrxn = 0.1558kj/K**

Thus , ΔG = ΔH - TΔS

= -2657 - ( 298 × 0.1558kj/K )

**ΔG = -2720kj **

Hence , the value of **ΔG **is** -2703kj** .

Learn more** combustion reaction** here :

brainly.com/question/13251946

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<u>**Answer:**</u>** The speed of the electron is **

<u>**Explanation:**</u>

**To calculate the speed of electron for given wavelength, we use the equation given by De-Broglie's, which is:**

where,

= De-Broglie's wavelength =

h = Planck's constant =

m = mass of the electron =

v = speed of the electron = ?

**Putting values in above equation, we get:**

**Hence, the speed of the electron is **