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Anarel [89]
3 years ago
9

______ molecules have no net electrical charge

Chemistry
1 answer:
Reptile [31]3 years ago
4 0

Answer:

A nonpolar molecule has no separation of charge

Explanation:

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How much heat is released (in calories) by a sample of Pop Tarts burned in a calorimeter if the temperature of the 100 grams of
algol13

Answer:

19437 J

Explanation:

mass = 100 g

Initial Temperature = 23.5°C

Final Temperature = 70°C

Temperature change, ΔT = 70 - 23.5 = 46.5

Heat = ?

The parameters are related by the equation;

H = mc ΔT

where c = specific heat capacity = 4.18 J/g°C

H = 100 * 4.18 * 46.5 = 19437 J

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3 years ago
At constant pressure, density of gas is inversely proportional to its temperature. This is how hot air balloon is floating in ai
Arturiano [62]

Answer:

1.08 g/L is the density of air.

Explanation:

Pressure of the gas = P (atm)

Volume of the gas = V (L)

Moles of gas = n = \frac{w(g)}{M(g/mol)}

Temperature of the gas = T (K)

PV=nRt

PV=\frac{w}{M}\times RT

PM=\frac{w}{V}RT=DRT

where:

D = density of the gas = \frac{Mass}{Volume}

R = universal gas constant

w = Mass of the gas

M =Molar mass of the gas

Given = P = 1.0 atm , T = 54°C = 327.15 K

Average molar mass of the gas = 29 g/mol

Putting all the given values in above equation.

1 atm\times 29 g/mol=D\times 0.0821 atm L/mol K\times 327.15 K

D=\frac{1 atm\times 29 g/mol}{0.0821 atm L/mol K\times 327.15 K}

D = 1.08 g/L

1.08 g/L is the density of air.

3 0
3 years ago
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ch4aika [34]

Answer:

b.fission, because the reaction absorbed energy

Explanation:

6 0
3 years ago
Which unit would you use to measure the mass of a student desk?
Lubov Fominskaja [6]

Answer:

inches or feet depends on the type of desk

Explanation:

6 0
3 years ago
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For many purposes we can treat methane (CH) as an ideal gas at temperatures above its boiling point of - 161. °C. Suppose the te
AysviL [449]

Answer:

Explanation:

T₁ = 100 + 273 = 373K

T₂ = 273 + 119 = 392 K

V₁ = initial volume

V₂ = Final volume

P₁ = P₁

P₂ = .85P₁

Using gas law equation

\frac{P_1\times V_1}{T_1} =\frac{P_2\times V_2}{T_2}

= \frac{P_1\times V_1}{373} =\frac{.85P_1\times V_2}{392}

V₂ = 1.236 V₁

% increase in volume

= V₂-V₁ / V₁  x 100

= (1.236 V₁ - V₁ / V₁)x 100

= .236 x 100

= 23.6 % .

5 0
3 years ago
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