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oksian1 [2.3K]
2 years ago
5

If f(x)=x/2-3 and g(x)=3x²+x-6 find (f+g)(x)

Mathematics
1 answer:
Ber [7]2 years ago
7 0

Answer:

(f+g)(x) = 3x² + (3/2)X - 9

Step-by-step explanation:

f(x) = 1/2*x - 3

g(x) = 3x²+x-6

then (f+g)(x) i f(x) + g(x)

1/2*x - 3 + 3x²+x-6

3x² + 1.5X - 9

3x² + (3/2)X - 9

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Answer:

angles must add up to 180°

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Question 5
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Explanation : If 66 is a factor of this unknown value, then 22 must be as well considering that 22 is a factor off 66. Let's say that this large value is 330. It is a multiple of 66, as 66 * 5 = 330. At the same time 22 * 15 = 330, so 330 is a multiple of 22 as well - or vice versa, 12 is a factor of 330.

We can also tell that 15, 22 fit into 330 through another approach. 22 * 3 = 66, and 66 * 5 = 330, so 5 * 3 = 15 - the same value. This proves that 22 will always be a factor of a value that is the factor of 66.

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Consider this function. f(x)=6log2x-3 over which interval is function f increasing at the greatest rate?
m_a_m_a [10]

The function increased at the highest rate in the interval [1/8, 1/2], as can be seen from the function value and its interval values.

<h3>What is  maxima and minima?</h3>

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<h3>Why do we use maxima and minima?</h3>

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<h3>According to the given information we have:</h3>

f(x)=6log2x-3

For the interval x ∈[2, 6]

f(x) ∈ [-0.678, 3]

For the interval x ∈ [1/8, 1/2]

f(x) ∈ [ -9.96, -5.32]

For the interval x ∈ [1, 2]

f(x) ∈ [-3, -0.67]

For the interval x∈ [1/2, 1]

f(x) ∈ [-5.32, -3]

The function increased at the highest rate in the interval [1/8, 1/2], as can be seen from the function value and its interval values.

To know more about  interval values visit:

brainly.com/question/14264237

#SPJ4

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2 years ago
Jeremy raised $250 for charity last year. This year he raised 20% more than he raised last year. How much money did Jeremy raise
Lesechka [4]
You would find this by doing 250 times 20% which is .2 and you would get 50 so you would add 250 plus 50 and get 300.
The answer is $300
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3 years ago
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I need help with these 3 questions . these questions were the ones i got confused on.
olga55 [171]

1) AB + BC = AC. Plug in for each of these, you get:

x - 3 + 7x + 12 = 6x + 23

Combine like terms:

8x + 15 = 6x + 23

Subtract 6x from both sides and subtract 15 from both sides so you get variables on one side and constants on the other.

8x - 6x = 23 - 15

2x = 8

Divide both sides by 2 to isolate the variable.

x = 8/2 = 4

x = 4.

2) Same thing to start out. AB + BC = AC.

2y + 5 + 3y - 4 = 7y - 5

Combine like terms:

5y + 1 = 7y - 5

Subtract 5y from both sides and add 5 to both sides so that you get variables on one side and constants on the other.

1 + 5 = 7y - 5y

6 = 2y

Divide both sides by 2 to isolate the variable.

y = 6/2 = 3

y = 3.

Now we must plug in our y-value. If AB = BC, then point is the mid-point.

2y + 5 = 3y - 4

2(3) + 5 = 3(3) - 4

6 + 5 = 9 - 4

11 ≠ 5

Point B is not the midpoint.

3) AH + HS = AS

5b - 1 + 12b + 7 = 8b + 9

Combine like terms:

17b + 6 = 8b + 9

Subtract 8b from both sides and 6 from both sides to get variables on one side and constants on the other:

17b - 8b = 9 - 6

9b = 3

Divide by 9 on both sides to isolate the variable:

b = 3/9 = 1/3.

Now, we have to find AS. So plug in your b-value into the AS equation.

AS = 8b + 9

8(1/3) + 9

8/3 + 9 -> 8/3 + 27/3 = 35/3 = 11 and 2/3

AS = 11 and 2/3 units

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