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pashok25 [27]
1 year ago
6

Triangle rst is dilated by a scale factor of 5 to form triangle r's't'. side r's' measures 40. what is the measure of side rs?

Mathematics
1 answer:
LenKa [72]1 year ago
5 0

Answer: 8

Step-by-step explanation:

We know that scale factor = (image)/(preimage).

Substituting in what we have,

5=\frac{R'S'}{RS}\\\\5=\frac{40}{RS}\\\\RS=\boxed{8}

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A quadratic equation is shown below:
Mariulka [41]

hello : 

<span>help :
<span>the discriminat of each quadratic equation : ax²+bx+c=0 ....(a ≠ 0) is :
Δ = b² -4ac
1 )  Δ > 0  the equation has two reals solutions : x =  (-b±√Δ)/2a</span>
2 ) Δ = 0 : one solution : x = -b/2a
3 ) Δ < 0 : no reals solutions</span>

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How much water should you have in a severe weather emergency supply kit?
Y_Kistochka [10]

Answer: u should have at least i gallon per person per day

8 0
2 years ago
3 csc^2(2x) + 2 cosec 2x = 1-cot^2(2x)
asambeis [7]

I am assuming you want to solve for x:-

Now cosec^2 2x = 1 - cot^2 2x  so the equation becomes

3 cosec^2(2x) + 2 cosec 2x =  cosec^2 2x

2 cosec^2 2x + 2 cosec 2x = 0

2 cosec 2x (  cosec 2x + 1) = 0

so 2 cosec 2x = 0  or    cosec 2x = -1

cosec 2x = 0  or cosec 2x = -1

cosec 2x = 0  is indeterminate so we ignore the first one

cosec 2x = -1  can be written as 1 / sin 2x = -1

so sin 2x = -1  

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3 0
3 years ago
When grading an exam, 90% of a professor's 50 students passed. If the professor randomly selected 10 exams, what is the probabil
Damm [24]

Using the binomial distribution, it is found that there is a:

a) 0.9298 = 92.98% probability that at least 8 of them passed.

b) 0.0001 = 0.01% probability that fewer than 5 passed.

For each student, there are only two possible outcomes, either they passed, or they did not pass. The probability of a student passing is independent of any other student, hence, the binomial distribution is used to solve this question.

<h3>What is the binomial probability distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 90% of the students passed, hence p = 0.9.
  • The professor randomly selected 10 exams, hence n = 10.

Item a:

The probability is:

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{10,8}.(0.9)^{8}.(0.1)^{2} = 0.1937

P(X = 9) = C_{10,9}.(0.9)^{9}.(0.1)^{1} = 0.3874

P(X = 10) = C_{10,10}.(0.9)^{10}.(0.1)^{0} = 0.3487

Then:

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1937 + 0.3874 + 0.3487 = 0.9298

0.9298 = 92.98% probability that at least 8 of them passed.

Item b:

The probability is:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

Using the binomial formula, as in item a, to find each probability, then adding them, it is found that:

P(X < 5) = 0.0001

Hence:

0.0001 = 0.01% probability that fewer than 5 passed.

You can learn more about the the binomial distribution at brainly.com/question/24863377

3 0
2 years ago
25 Points!!! Help plzz!! Will give Brainliest!!!
Lady_Fox [76]

Answer:

Option C : ASA

Step-by-step explanation:

Side WS Lies between ∠W and ∠S

Side NT lies between ∠N and ∠T

Hence the theorem which supports the congruency  of the two triangles

is ASA

Angle - Side - Angle

3 0
2 years ago
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