1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nimfa-mama [501]
3 years ago
6

If 10,500 is deposited in a compound interest account paying 2.99% interest annually, how much will be in the account after 5 ye

ars? Round your answer to the nearest cent.
Quality work shown and correct answer will be awarded brainliest.
Mathematics
1 answer:
Neko [114]3 years ago
8 0
Hello,

Your brainliest answer would be:

10.500 ----- 100% x ----2,99% ---- x = (2,99*10500)/100 = 313,95 this mony will get annually so what will be for 5 years 313,95*5=1569,75 - and you need assuming 10500 with 1569,75 for you get the right answer 10500 + 1569,75 = 12069,75 - so than will have after 5 years on account 12069,75 money

Plz mark me brainliest!

Hope this helps!
You might be interested in
How to write an equivalent expression for n times a using only addition
Alina [70]
How to write an equivalent expression for n time a using o
6 0
3 years ago
I need help answer ASAP I’m confused
katrin [286]

Answer:

Step-by-step explanation:

You can plug in the 294 for A and solve

4 0
3 years ago
HELP PLEASE!!! 10 PTS!!
allsm [11]

Answer:

m∠DEC = 78°

Step-by-step explanation:

Given information: AC = AD, AB⊥BD, m∠DAC = 44° and CE bisects ∠ACD.

If two sides of a triangles are congruent then the opposite angles of congruent sides are congruent.

AC = AD                 (Given)

\angle ADC\cong \angle ACD

m\angle ADC=m\angle ACD

According to the angle sum property, the sum of interior angles of a triangle is 180°.

m\angle ADC+m\angle ACD+m\angle DAC=180

m\angle ACD+m\angle ACD+44=180

2m\angle ACD=180-44

2m\angle ACD=136

Divide both sides by 2.

m\angle ACD=68

CE bisects ∠ACD.

m\angle ACE=m\angle DCE=\dfrac{\angle ACD}{2}

m\angle ACE=m\angle DCE=\dfrac{68}{2}

m\angle ACE=m\angle DCE=34

Use angle sum property in triangle CDE,

m\angle CDE+m\angle DCE+m\angle DEC=180

68+34+m\angle DEC=180

68+34+m\angle DEC=180

102+m\angle DEC=180

Subtract 102 from both sides.

m\angle DEC=180-102

m\angle DEC=78

Therefore, the measure of angle DEC is 78°.

6 0
3 years ago
Select the correct answer. Why is it important to look at your audience when speaking? A. So that they don't get bored B. So tha
Norma-Jean [14]

Answer:

c

Step-by-step explanation:

so you can get the attention and intrest them in your speech

7 0
3 years ago
Read 2 more answers
Greatest to least - 1/2, 3/5, 3/7
Natalka [10]
3/7, 3/5, 1/2 is the answer it starts from the lowest to the lagest
4 0
3 years ago
Other questions:
  • max is making a rectangular garden that is 5 feet less than twice its width. If the perimeter of the garden is 80 feet, what wil
    10·2 answers
  • Consider the two triangles shown. Which statement is true?
    15·2 answers
  • Janice rode her bike at an average of 12 miles per hour for 3 hours. Renee rode her bike at an average of 14 miles per hour for
    7·2 answers
  • Over the last 3  evenings, Keisha received a total of 81  phone calls at the call center. The first evening, she received 6  few
    13·1 answer
  • John has a rectangular-shaped field whose length is 62.5 yards and width is 45.3 yards. The area of the field is ________ square
    14·1 answer
  • 10(23+7)=100ℓ+100ℓ What is the value of \large\ellℓell in the equation above?
    11·1 answer
  • What is the area of this parallelogram? A.16 B. 25 C.25 D.30
    12·2 answers
  • Use the drawing tool(s) to form the correct answer on the provided graph. The table below represents an exponential function, g,
    14·1 answer
  • The mass of substances left in a sample
    9·1 answer
  • Yolanda is currently an 18 year old senior. If she works from the time she finishes her education, how old must she be to collec
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!