They are both equal to below zero
Answer:
Infinitely many solutions.
Step-by-step explanation:
Let's begin by carrying out the indicated multiplications, which must be done before any addition or subtraction:
2(8r+5)-3=4(4r-1)+11 becomes 16r + 10 - 3 = 16r - 4 + 11.
Subtracting 16r from both sides, we get 10 - 3 = - 4 + 11, or 7 = 7
This is always true, so we can conclude that this equation has infinitely many solutions.
To do these, always convert the percents to decimals, so you can subtract it from 1. Remember, 1 is the whole. When you subtract the part that's taken off, you are left with what you have to pay. If you have 20% off of $100, then you are paying for 80% of $100. **of means to multiply** so you would multiply: 0.8X100, which would be $80.
First, multiply 125x0.8
Multiply that answer by 0.7
You should get B. $70
3) multiple 22.90x0.93
You should get D
Answer:
-2
Step-by-step explanation:
0.5a=2a+3
a=-2
PLEASE MARK BRAINLIEST
Answer:
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Step-by-step explanation:

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