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bagirrra123 [75]
3 years ago
10

Mrs. Farad goes to an office supply store to buy 6 markers and a poster board for each of the 20 girls in her troop. Let m repre

sent the cost of 1 marker and b represent the cost of 1 poster board. Write two different expressions that represent the total amount Mrs. Farad paid for her purchase.
Mathematics
1 answer:
Elina [12.6K]3 years ago
8 0

Answer:

ok so if m is maker and b is poster then

6m+b since she buys 6 markers and 1 poster or

b+6m if she bought it in a different order

Hope This Helps!!!

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Which recursive sequence produced sequence 6, -26, 102,
LekaFEV [45]
The answer would be the first person said 6, -26,102
4 0
3 years ago
Please don't leave half an answer for the points!
vovikov84 [41]

Answer:

  1. T . . . labeling shown below
  2. U
  3. R
  4. S

Step-by-step explanation:

Matrix multiplication of A(a rows, b columns) and B(b rows, c columns) will result in a product matrix of AB(a rows, c columns). This fact can be used to reduce the number of candidates for each product.

For the given factor tiles, the resulting product dimensions will be ...

  [2, 3]  [3, 2]  [2, 2]   ⇒  Q, R, S

  [2, 3]  [3, 3]  [3, 2]   ⇒   T, U, V

  [3, 3]   ⇒   W

1. For this 2×3 product, candidates are Q and T. The upper left term for the product in Q is (2)(3) +(1)(7) +(0)(8) = 13. The appropriate choice is T.

2. For this 3×3 product, candidates are U and W. The upper left term for the product in U is 9(2) +1(2) +9(5) +5(1) = 18 +2 +45 +5 = 70. The appropriate choice is U.

3. For this 3×2 product, candidates are R and V. The upper left term for the product in R is 1(4) +2(0) +4(1) = 4 +0 +4 = 8. The appropriate choice is R.

4. For this 2×2 product, there is only one candidate: S.

5 0
2 years ago
According to an​ airline, flights on a certain route are on time 80 ​% of the time. suppose 10 flights are randomly selected and
natulia [17]
<span>(a) This is a binomial experiment since there are only two possible results for each data point: a flight is either on time (p = 80% = 0.8) or late (q = 1 - p = 1 - 0.8 = 0.2).
​(b) Using the formula:</span><span>
P(r out of n) = (nCr)(p^r)(q^(n-r)), where n = 10 flights, r = the number of flights that arrive on time:
P(7/10) = (10C7)(0.8)^7 (0.2)^(10 - 7) = 0.2013
Therefore, there is a 0.2013 chance that exactly 7 of 10 flights will arrive on time.
​(c) Fewer than 7 flights are on time means that we must add up the probabilities for P(0/10) up to P(6/10).
Following the same formula (this can be done using a summation on a calculator, or using Excel, to make things faster):
P(0/10) + P(1/10) + ... + P(6/10) = 0.1209
This means that there is a 0.1209 chance that less than 7 flights will be on time.
​(d) The probability that at least 7 flights are on time is the exact opposite of part (c), where less than 7 flights are on time. So instead of calculating each formula from scratch, we can simply subtract the answer in part (c) from 1.
1 - 0.1209 = 0.8791.
So there is a 0.8791 chance that at least 7 flights arrive on time.
(e) For this, we must add up P(5/10) + P(6/10) + P(7/10), which gives us
0.0264 + 0.0881 + 0.2013 = 0.3158, so the probability that between 5 to 7 flights arrive on time is 0.3158.
</span>
6 0
3 years ago
Math problem I need help on
JulijaS [17]

Answer:I think the answer is

1. x=8

Step-by-step explanation:

1. X=8

2. X=1⅓

3. 0x=-12

4. -8x=0

5. 0x=24

8 0
3 years ago
E
xz_007 [3.2K]

Answer:

1) n = 84

2) n = 78

3) n = 24

4) n = 16

5) n = 35

Step-by-step explanation:

To solve each proportion, we apply cross multiplication.

Question 1:

\frac{5}{12} = \frac{35}{n}

5n = 35*12

Simplifying both sides by 5

n = 7*12 = 84

Question 2:

\frac{n}{52} = \frac{180}{120}

120n = 52*180

Simplifying both sides by 20

6n = 52*9

Simplifying by 3

2n = 52*3

Simplifying by 2

n = 26*3 = 78

Question 3:

\frac{18}{n} = \frac{21}{28}

21n = 18*28

Simplifying both sides by 7

3n = 18*4

Simplifying both sides by 3

n = 6*4 = 24

Question 4:

\frac{n}{4} = \frac{24}{6}

\frac{n}{4} = 4

n = 16

Question 5:

\frac{10}{16} = \frac{n}{56}

16n = 56*10

Simplifying by 2, both sides

8n = 56*5

Simplifying by 8, both sides

n = 7*5 = 35

4 0
3 years ago
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