Question

. Find their present ages. 6 years ago a man's age was six times the age of his son. 4 years hence, thrice his age will be equal to eight times his son's age. What are their present ages?​

Answer 1

The present age of the man is 36 years and his son is 11 years.

Answer:

Solution given:

let the age of man be x.

and his son be y.

By question

x-6=6(y-6)

x=6y-36+6

x=6y-30. ......(1)

and

3(x+4)=8(y+4)

3x+12=8y+32

3x=8y+32-12

3x=8y+20. ...(2)

substituting value of x in equation 2 ,we get

3(6y-30)=8y+20

18y-90=8y+20

18y-8y=90+20

10y=110

y=110/10

y=11 years

again substituting value of y in equation 1 we get

x=6*11-30

x=66-30

x=36 years