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Mekhanik [1.2K]
1 year ago
9

Find the sum of these polynomials.

Mathematics
2 answers:
Crank1 year ago
8 0

Answer:

C. 10x²-x+13

Step-by-step explanation:

1. Add the numbers

x^2 - x + 7 + 9x^2 + 6

x^2 - x + 13 + 9x^2

2. Combine like terms

x^2 - x + 13 + 9x^2

10x^2 - x + 13

Genrish500 [490]1 year ago
7 0

Answer:

C

Step-by-step explanation:

add the two x^2 parts    =  10 x^2

 so answer is B or C

  add the constants   7 + 6 = 13     so answer C

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If a movie starts at 10:40am and lasts for 1h and 59min, then what time should the movie end.
OverLord2011 [107]

Answer:

12:39

Step-by-step explanation:

First, to make it easier, round the amount of time the movie lasts to the nearest hour. In this case, the movie "lasts" for 2 hours.

Add 2 hours to 10:40am. Note that when it hits 12, the am becomes pm.

10:40 + 2:00 = 12:40

Now, subtract 1 minute from the amount (1 hr 60 min - 1 hr 59 min = 1 min)

12:40 - 0:01 = 12:39

12:39 pm should be the time the movie ends.

~

7 0
3 years ago
Read 2 more answers
Hi, I need some help with the last question of the first problem and the answer to the second page.
bulgar [2K]

Answer:

46.9 for the first one

Step-by-step explanation:

So sorry if i'm wrong <3

6 0
2 years ago
Hello, Can someone please explain on how to do this? thank you!
Marrrta [24]
Steps:

1) determine the domain

2) determine the extreme limits of the function

3) determine critical points (where the derivative is zero)

4) determine the intercepts with the axis

5) do a table

6) put the data on a system of coordinates

7) graph: join the points with the best smooth curve

Solution:

1) domain

The logarithmic function is defined for positive real numbers, then you need to state x - 3 > 0

=> x > 3 <-------- domain

2) extreme limits of the function

Limit log (x - 3) when x → ∞ = ∞

Limit log (x - 3) when x → 3+ = - ∞ => the line x = 3 is a vertical asymptote

3) critical points

dy / dx = 0 => 1 / x - 3 which is never true, so there are not critical points (not relative maxima or minima)

4) determine the intercepts with the axis

x-intercept: y = 0 => log (x - 3) = 0 => x - 3 = 1 => x = 4

y-intercept: The function never intercepts the y-axis because x cannot not be 0.

5) do a table

 x                          y = log (x - 3)

limit x → 3+            - ∞

3.000000001        log (3.000000001 -3) = -9

3.0001                  log (3.0001 - 3) = - 4

3.1                       log (3.1 - 3) = - 1

4                          log (4 - 3) = 0

13                       log (13 - 3) = 1

103                     log (103 - 3) = 10

lim x → ∞             ∞

Now, with all that information you can graph the function: put the data on the coordinate system and join the points with a smooth curve.
7 0
3 years ago
Read 2 more answers
The polygons are similar. The area of one polygon is given. Find the area of the other polygon.
Fantom [35]

Answer:

108 ft²

Step-by-step explanation:

For the polygon on the left, we are given the length of one side (3 ft) and the total area (27 ft²). With this information, we can determine the length of the other side - 9 ft. I found this by dividing 27 ft² by 3 ft, giving me the final result of 9 ft.

Next, we have to find the other side of the polygon on the <em>right</em> so we can ultimately determine its area. It looks like there is a scale factor of 2 between the two polygons, since 3 × 2 = 6. We know that the bottom side of the left polygon is 9, so multiplying 9 by 2 should give us the bottom side of the polygon on the right. 9 × 2 = 18.

Now, we have the side lengths for the polygon on the right and can determine its area. What is 6 ft × 18 ft? Well, the answer is 107 ft², and this is the answer to the question.

Hopefully that's helpful! :)

5 0
2 years ago
In the diagram of circle R, m∠FGH is 50°. What is m? 130° 230° 260° 310°
omeli [17]

we know that

The measurement of the exterior angle is the semi-difference of the arcs which comprises

In this problem

∠FGH is the exterior angle

∠FGH=50\°

∠FGH=\frac{1}{2}(arc\ FEH-arc\ FH)

50\°=\frac{1}{2}(arc\ FEH-arc\ FH)

100\°=(arc\ FEH-arc\ FH)  -----> equation A

arc\ FEH+arc\ FH=360\°

arc\ FH=360\°-arc\ FEH --------> equation B

Substitute equation B in equation A

100\°=(arc\ FEH-[360\°-arc\ FEH])

100\°=2arc\ FEH-360\°

2arc\ FEH=360\°+100\°

arc\ FEH=230\°

therefore

<u>The answer is</u>

The measure of arc FEH is equal to 230\°

6 0
3 years ago
Read 2 more answers
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