Question 5 of 20 (___)^2=(secx-1)(secx+1) answer here:

1 answer:

5 0

42 because there is something to the equation. Where is will most likely make u fail so don’t take my answer because u will fail

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which of the following properties could be used to rewrite the expression (2/3•1/5)•5/2 as 2/3•(5/2•(5/2•1/5) sorry to ask Su ma

slamgirl [31]

The original expression is given by:
$( \frac{2}{3}*\frac{1}{5})*\frac{5}{2}$
The correct way to rewrite the expression is given by:
$\frac{2}{3}*(\frac{5}{2}*\frac{1}{5})
$
For this, we use two properties:

Associative property:
The way of grouping the factors does not change the result of the multiplication:
$\frac{2}{3}*(\frac{1}{5}*\frac{5}{2})$

Commutative property:
The order of the factors does not vary the product:
$\frac{2}{3}*(\frac{5}{2}*\frac{1}{5})$

8 0

3 years ago

Kyra is finding the area of the circle. She cuts the circle into equal sectors and arranges them into the shape of a parallelogr

Vinvika [58]

Option 1. 9.42×3 in² is the correct option.

Step-by-step explanation:

As it has been given in the question that Kyra has arranged the circle sectors in the shape of a parallelogram.
Side of a parallelogram = 9.42 in. and height of this parallelogram is 3 in.
Now we know the formula of the area of a parallelogram = length × height
Area = 9.42 × 3 in².
So the area of this arrangement of the sectors = 9.42×3 in².

8 0

3 years ago

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What number is halfway between 13 and 31

ankoles [38]

To find the answer to that, you have to see how many numbers are between 13 and 31. There are 18 numbers between 13 and 31. Divide 18 by 2 and you will get the number halfway. 9 is halfway between 13 and 31. So, add 9 to 13 and you get 22.

The answer is 22.

Hope I helped

4 0

3 years ago

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Solve for the specified variable <br> ax-by=8 (b)

Lady_Fox [76]

Ax + by = 8

Subtract ax from both sides.

by = 8 - ax

Divide both sides by y.

b = (8-ax)/y

7 0

3 years ago

THE FLORIDA EVERGLADES WELCOMES ABOUT 2X10^3 VISITORS PER DAY. Basedon this ,about how many visitors come to the everglades per

lesya [120]