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sashaice [31]
3 years ago
7

Below are 10 different metric prefixes and their abbreviations. Match them up. :)

Chemistry
1 answer:
Sladkaya [172]3 years ago
7 0

Answer:

1.G → giga  

2.da → deca

3.n → nano

4.m → milli

5.M → mega

6.k → kilo

7.c → centi

8.d → deci

9.h → hecto

10.µ → micro

Explanation:

In descending order:

1.G → giga (1 . 10⁹)  

5.M → mega (1 . 10⁶)

6.k → kilo (1 . 10³)

9.h → hecto (1 . 10²)

2.da → deca (1 . 10¹)

8.d → deci (1 . 10⁻¹)

7.c → centi (1 . 10⁻²)

4.m → milli (1 . 10⁻³)

10.µ → micro  (1 . 10⁻⁶)

3.n → nano (1 . 10⁻⁹)

In example:

1000000 m = 1 Mm

0,000000001 m = 1 nm

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Because they create their own food, they are considered as producers.
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For the reaction shown, calculate how many grams of oxygen form when each quantity of reactant completely reacts.
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Explanation:

Molar mass of KClO_{3} = 39.1 + 35.5 + 3(16.0) = 122.6 g

Molar mass of KCl = 39.1 + 35.5 = 74.6 g

Molar mass of O_{2} = 32.0 g

According to the equation, 2 moles of KClO_{3} reacts to give 3 moles of oxygen.

Therefore, 2 (122.6) = 245.2 g of KClO_{3} will give 3 (32.0) = 96.0 g of oxygen. Thus, 245.2 g of KClO_{3} gives 96.0 g of oxygen.

(a) Calculate the amount of oxygen given by 2.72 g of KClO_{3} as follows.

       \frac {96g}{245.2g} \times 2.72 g = 1.06 g of O_{2}


(b) Calculate the amount of oxygen given by 0.361 g of KClO_{3} as follows.

    \frac {96g}{245.2g} \times 0.361 g = 0.141 g of O_{2}


c) Calculate the amount of oxygen given by 83.6 kg KClO_{3} as follows.  

    \frac {96g}{245.2g} \times 83.6 g = 32.731 kg of O_{2}

Convert kg into grams as follows.

    \frac{32.731 kg}{1 kg} \times 1000 g = 32731 g of O_{2}


(d) Calculate the amount of oxygen given by 22.5 mg of KClO_{3} as follows.  

    \frac {96g}{245.2g} \times 22.5 mg = 8.79 mg

Convert mg into grams as follows.

  \frac{8.79 mg}{1 mg}\times 10^{-3} g = 8.79 \times 10^{-3} g of O_{2}

8 0
3 years ago
25cc of 5 % NaOH solution neutralized 30cc of h2sO4 solution. Whatis normality of H2SO4?
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The normality of the H₂SO₄ that reacted with 25cc of 5 % NaOH solution is 1.1 N.

<h3>What is the molarity of 5% NaOH?</h3>

The molarity of 5% NaOH is 1.32 M

25 cc of NaOH neutralized 30cc of H₂SO₄ solution.

Equation of reaction is given below:

  • 2 NaOH + H₂SO₄ ---> Na₂SO₄ + 2 H₂O

Molarity of H₂SO₄ = 1.32 x 1 x 25/(30 x 2) = 0.55 M

  • Normality = Molarity × moles of H⁺ ions per mole of acid

moles of H⁺ ions per mole of H₂SO₄ = 2

Normality of H₂SO₄ = 0.55 x 2 = 1.1 N

In conclusion, the normality of an acid is determined from the molarity and the moles of H⁺ ions per mole of acid.

Learn more about normality at: brainly.com/question/22817773

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7 0
2 years ago
A student listed the characteristics of chemical and nuclear reactions.
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Answer:

D. It is a chemical reaction because the total mass remains the same when new substances are formed.

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A chemical reaction is represented by a chemical equation which show the reactant and products. Reactants are written on left side of arrow while products are written on right side. The number of atoms are remain same however arrangement of atoms is different on both side.

For example:

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it is known from balanced chemical equation that 6 moles of carbon dioxide react with the six moles of water and created one mole of glucose and six mole of oxygen. The number of atoms are same on both side however arrangement of atoms is different.

While in case of nuclear reaction small change in mass take place.

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