Answer:
positive plate
E = 5.764 KV / m
W = 490eV or 7.85 * 10^-17 J
E_p = 4.74 *10^(-12) eV
E_k = 490 eV
Explanation:
part a
The potential difference between two plates = 490 V
Distance between two plates = 8.5 cm
Answer: The positive plate is at higher potential because of convention.
part b
Electric Field between the plates
E = V / d
E = 490 / 0.085 = 5.764 KV / m
Answer: Electric Field between the plates E = 5.764 KV / m
part c
Work done by electric field
W = V*q
W = 490 * 1.602*10^-19
W = 7.85 * 10^-17 J
or W = 490 eV
Answer: Work done by electric field W = 490eV or 7.85 * 10^-17 J
part d
Potential Energy of an electron gained:
E_p = m_e * g * d / (1.602*10^-19)
E_p = 9.109*10^-31* 9.81 * 0.085 / (1.602*10^-19)
E_p = 4.74 *10^(-12) eV
Very very small E_p approximately 0
Answer: Potential Energy of an electron gained E_p = 4.74 *10^(-12) eV or 0.
part e
Kinetic Energy of an electron gained:
W - E_p = E_k
E_k = 490eV - 4.74*10^(-12)eV
E_k = 490 eV
Answer: Kinetic Energy of an electron gained E_k = 490 eV
