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user100 [1]
2 years ago
7

How does enormous energy get released from the sun?

Physics
1 answer:
Nezavi [6.7K]2 years ago
7 0

Enormous energy get released from the sun due to fusion reaction.

<h3>How does enormous energy get released from the sun?</h3>

Sun can generate enormous energy due to nuclear fusion. In this process, high temperature and pressure in the core of the sun force the nuclei to separate from their electrons which results in the  formation of one Helium atom releasing a large amount of energy.

So we can conclude that enormous energy get released from the sun due to fusion reaction.

Learn more about energy here: brainly.com/question/13881533

#SPJ1

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Which is true about a concave mirror? Incident rays that are parallel to the central axis are dispersed but will be perceived as
Reil [10]

Answer:

'Incident rays that are parallel to the central axis are sent through a point on the near side of the mirror'.

Explanation:

The question is incomplete, find the complete question in the comment section.

Concave mirrors is an example of a curved mirror. The outer surface of a concave mirror is always coated. On the concave mirror, we have what is called the central axis or principal axis which is a line cutting through the center of the mirror. The points located on this axis are the Pole, the principal focus and the centre of curvature. <em>The focus point is close to the curved  mirror than the centre of curvature.</em>

<em></em>

During the formation of images, one of the incident rays (rays striking the plane surface) coming from the object and parallel to the principal axis, converges at the focus point after reflection because all incident rays striking the surface are meant to reflect out. <em>All incident light striking the surface all converges at a point on the central axis known as the focus.</em>

Based on the explanation above, it can be concluded that 'Incident rays that are parallel to the central axis are sent through a point on the near side of the mirror'.

5 0
3 years ago
Joe is camping in the mountains when a storm suddenly hits. Joe hears the thunder and sees the lightning. A lightning strike sta
svp [43]

Answer:

Hypothalamus

Explanation:

Dealing with a storm is a stressful situation especially when the fire has started in the forest. These multiple signals are processed by hypothalamus that is located in the base of the brain and send the processed information to Pitutary gland that makes primary secretions to activate the renal medulla and a fight-or-flight response to stimuli is generated by rushing the body with energy induced by Adrenaline

8 0
3 years ago
If a sinusoidal electromagnetic wave with intensity 18 W/m2 has an electric field of amplitude E, then a 36 W/m2 wave of the sam
Neporo4naja [7]

Answer:

The  correct option is D

Explanation:

From the question we are told that

  The intensity of the first  electromagnetic wave is  I =  18 \  W/m^2

  The amplitude of the electric field is  E_{max}_1 =A

   The intensity of the second electromagnetic wave is  I =  36 \  W/m^2

Generally the an electromagnetic wave intensity is mathematically represented as

       I  =  \frac{1}{2} *  \epsilon_o  * c  * E_{max}^2

Looking at this equation we see that

     I \ \ \alpha  \ \ E^2_{max}

=>  \frac{I_1}{I_2}  =  [ \frac{ E_{max}_1}{ E_{max}_2} ] ^2

=>   E_{max}_2 = \sqrt{\frac{x}{y} }  *  E_{max}_1

=>  E_{max}_2 = \sqrt{\frac{36}{18} }  * E        

=>  E_{max}_2 = \sqrt{2 }  E        

5 0
3 years ago
Some Physics questions! Please help!
lesantik [10]

1) 260 km/h

Let's use the following convention:

positive x-direction = east

positive y-direction = north

Here we have to find the north component of the velocity's airplane, which means we have to find its y-component.

We can use the formula:

v_y = v sin \theta

where

v = 750 km/h is the magnitude of the plane's velocity

\theta=20.0^{\circ} is the angle between the direction of the plane and the positive x-axis

Substituting,

v_y = (750)(sin 20)=256.5 km/h \sim 260 km/h

2) 24^{\circ} north of east

In order to find the direction of flight, we have to consider that the vector representing the displacement of the plane is the hypothenuse of a right triangle, of which the displacements along the east and north direction are the sides.

Therefore, we have

v_x = 220 km is the displacement towards east

v_y = 100 km is the displacement towards north

Therefore, the angle that gives the direction is given by

tan \theta = \frac{v_y}{v_x}

And substituting,

\theta =tan^{-1}( \frac{100}{200})=24^{\circ}

and this angle is measured north of east.

7 0
4 years ago
when an object is charged by contact, what kind of charge does the object have compared with the charge on the on the object giv
sveta [45]

Answer:

the charge that is given by the object is positive charge and the object which is taking the charge is negetively charged

Explanation:

5 0
3 years ago
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