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natta225 [31]
3 years ago
9

A hawk flies in a horizontal arc of radius 12.0 m at constant speed 4.00 m/s. (a) Find its centripetal acceleration. (b) It cont

inues to fly along the same horizontal arc, but increases its speed at the rate of 1.20 m/s2. Find the acceleration (magnitude and direction) in this situation at the moment the hawk’s speed is 4.00 m/s.
Physics
1 answer:
olya-2409 [2.1K]3 years ago
5 0

Answer:

a) a_c= 1.33 m/s^2

b) a= 1.79 m/s²

   θ = 41.98⁰

Explanation:

arc radius  = 12 m

constant speed = 4.00 m/s

(a) centripetal acceleration

     a_c=\frac{v^2}{R}

     a_c=\frac{4^2}{12}

                  = 1.33 m/s²

(b) now we have given

        a_t= \ 1.20 m/s^2

        now,

         a=\sqrt{a^2_c+ a^2_t}

         a=\sqrt{1.33^2+ 1.20^2}

            a= 1.79 m/s²

 direction

\theta = tan^{-1}(\frac{a_t}{a_r} )

\theta = tan^{-1}(\frac{1.2}{1.33} )

     θ = 41.98⁰

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