.1= a tenth.
.01= a hundreth.
.001= a thousandth.
So,
Four tenths, two hundredths, and three thousandths.
I hope this helps!
~kaikers
Answer:
I believe it's 4
Step-by-step explanation:
1) Use the pathagreom theorem; a^2+b^2=c^2
(The hypotenuse is always c. The other two legs can be either a or b.)
*use x for the unknown side*
1. Plug in the measurements
4^2+x^2=8.5^2
2. Solve
16+x^2=72.25
RADICAL(56.25)=> 7.5
The measure of the other side of the triangle (x) is= 7.5 m
2) Draw a square with the measure of 20 cm on each side.
Draw a diagonal line across the square.
(Use the pathagroeam theorem)
We know that the legs are 20, and 20. The hypotenuse is what we are trying to find (x).
1. Plug in the measurements
20^2+20^2=x^2
2. Solve
800= x^2
20 RADICAL(2)=> 28.28
The measure of the other side of the triangle (x) is= 28.3 cm
Answer:
15) 30°
16) 49.5°
Step-by-step explanation:
15) We solve using the Trigonometric function of Sine
sin θ = Opposite/Hypotenuse
Opposite = 12
Hypotenuse = 24
sinθ = 12/24
θ = arc sin(12/24)
= 30°
Approximately = 30°
16)We solve using the Trigonometric function of Cosine
cos θ = Adjacent/Hypotenuse
Adjacent = 13
Hypotenuse = 20
cos θ = 13/20
θ = arc cos (13/20)
= 49.458398126°
Approximately = 49.5°
Answer: the probability of getting a number less than 3 and tails is P 1/6
Step-by-step explanation:
Assuming that the dice and the coin are normal ones, we can expect that the probability for each outcome is about the same.
For the coin we have 2 outcomes, heads and tails, then each outcome has a probability of 1/2
The dice has 6 outcomes, and each outcome has a probability of 1/6.
Then the probability of rolling a number less than 3 is equal to the probability of rolling a 1 plus the probability of rolling a 2.
P1 + P2 = 1/6 + 1/6 = 2/6 = 1/3.
The probability of getting tails with the coin is 1/2.
Now, the joint for both events is equal to the product of the probabilities of each event, this is:
P = (1/3)*(1/2) = 1/6