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2 years ago

I want to know what is the pressure of the stratosphere simple numbers I’m in 6 grade

Physics

1 answer:

AURORKA [14]2 years ago

4 0

Answer:

This region of increasing temperatures is the stratosphere, spanning a pressure range from 100 millibars at its base to about 10 millibars at the stratopause, the top of the layer.

Explanation:

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How do scientist figure out how diseases start

mel-nik [20]

Answer: sometimes when people start having an outbreak of it, i guess

Explanation:

5 0

3 years ago

An ideal monatomic gas at 275 K expands adiabatically and reversibly to six times its volume. What is its final temperature (in

Gwar [14]

The final temperature is 83 K.

<u>Explanation</u>:

For an adiabatic process,

$T {V}^{\gamma - 1} = \text{constant}$

$\cfrac{{T}_{2}}{{T}_{1}} = {\left( \cfrac{{V}_{1}}{{V}_{2}} \right)}^{\gamma - 1}$

Given:-

${T}_{1} = 275 \; K$

${T}_{2} = T \left( \text{say} \right)$

${V}_{1} = V$

${V}_{2} = 6V$

$\gamma = \cfrac{5}{3} \;$ (the gas is monoatomic)

$\therefore \cfrac{T}{275} = {\left( \cfrac{V}{6V} \right)}^{\frac{5}{3} - 1}$

$\Rightarrow \cfrac{T}{275} = {\left( \cfrac{1}{6} \right)}^{\frac{2}{3}}$

T = 275 $\times$ 0.30

T = 83 K.

3 0

4 years ago

B. Jerome plays middle linebacker for South's varsity football team. In a game against

weqwewe [10]

Answer:

Option D

670 Kg.m/s

Explanation:

Initial momentum is given by mv=82*5.6=459.2 Kg.m/s (taking eastward as positive)

Final momentum is also mv but v being westward direction, we take it negative

Final momentum=82*-2.5= -205 Kg.m/s

Change in momentum=Final momentum-Initial momentum=-205-459.2=-664.2 Kg.m/s

Impulse=change in momentum=664.2 Kg.m/s rounded off as 670 Kg.m/s

4 0

3 years ago

a pool ball leaves a 0.60 meter high table with an initial high table with an initial horizontal velocity of 2.4m/s. predict the

timurjin [86]

Ball leaves the table of height 0.60 m

Initial speed of the ball is in horizontal direction which is 2.4 m/s

Now here we can say that time taken by the ball to hit the ground will be given by kinematics equation in vertical direction

$\Delta y = v_y*t + \frac{1}{2}at^2$

here in y direction we can say

$\Delta y = 0.60 m$

$v_y = 0$

$a = 9.8 m/s^2$ due to gravity

now from above equation we have

$0.60 = 0 + \frac{1}{2}*9.8*t^2$

$t = 0.35 s$

Now in the same time the distance that ball move in horizontal direction is given as

$d = v_x* t$

given that

$v_x = 2.4 m/s$

$d = 2.4 * 0.35$

$d = 0.84 m$

So it will move a total distance of 0.84 m where it will land

5 0

3 years ago

A 20Kg box is pushed across the floor at a constant velocity with a force of 200N. What is the

Shkiper50 [21]

Answer:

The kinetic coefficient of friction between the box and the floor is 1.020.

Explanation:

Let suppose that box is on horizontal ground. According to the Newton's Laws, an object has a net acceleration of zero when either is at rest or moves at constant velocity. Friction is a reaction to the external force that moves the box. Hence, the equation of equilibrium for the 20-Kg box is:

$\Sigma F = F-f = 0$ (Eq. 1)