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Vaselesa [24]
3 years ago
12

A motor does 8000j of work in 20 seconds. What is the power of the motor

Physics
1 answer:
lozanna [386]3 years ago
5 0
Power = work / time = 8000J / 20s = 400W

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State Archimedes' principle
OlgaM077 [116]

Explanation:

Archimedes' principle states that the upward buoyant force which is exerted on body when immersed  whether fully submerged or partially in the fluid is equal to weight of fluid which body displaces and this force acts in upward direction at center of mass of displaced fluid.

Thus,

<u>Weight of the displaced fluid = Weight of the object - Weight of object in fluid.</u>

6 0
3 years ago
A 297 g block is connected to a light spring with spring constant 4.34 N/m, and displaced 7.45 cm from equilibrium. It is then r
vagabundo [1.1K]

Answer:

x = A sin ω t       describes the displacement of the particle

v = A ω cos ω t

a = -A ω^2 sin ω t        

a (max) = -A ω^2     is the max acceleration (- can be ignored here)

ω = (K/ m)^1/2        for SHM

F = - K x^2     restoring force of spring

K = 4.34 / .0745^2 = 782 N / m

ω = (782 / .297)^1/2 = 51.3 / sec

a (max) = .0745 * 782 / .297 = 196 m / s^2

4 0
2 years ago
Which element is likely more reactive, and why?
erica [24]
Element 2 explanation just trust
6 0
2 years ago
Scientific _____ must be supported by observations and results many investigations and are not absolute
n200080 [17]
The correct answer you're looking for would be Theories.

7 0
3 years ago
10) Two students want to use a 12-meter long rope to create standing waves. They first measure the speed at which a single wave
zhannawk [14.2K]

Answer:

To create a second harmonic the rope must vibrate at the frequency of 3 Hz

Explanation:

First we find the fundamental frequency of the rope. The fundamental frequency is the frequency of the rope when it vibrates in only 1 loop. Therefore,

f₁ = v/2L

where,

v = speed of wave = 36 m/s

L = Length of rope = 12 m

f₁ = fundamental frequency

Therefore,

f₁ = (36 m/s)/2(12 m)

f₁ = 1.5 Hz

Now the frequency of nth harmonic is given in general, as:

fn = nf₁

where,

fn = frequency of nth harmonic

n = No. of Harmonic = 2

f₁ = fundamental frequency = 1.5 Hz

Therefore,

f₂ = (2)(1.5 Hz)

<u>f₂ = 3 Hz</u>

5 0
3 years ago
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