Answer:
The final velocity of apple and arrow after the collision is 2 m/s.
Explanation:
Given that,
Mass of an arrow, m = 0.5 kg
Initial velocity of the arrow, v = 10 m/s
Mass of an apple, m' = 2 kg
Initial velocity of the arrow, v' = 0 (at rest)
We need to find the final velocity of apple and arrow after the collision. After the collision, the arrow and the apple are stuck together. It is a case of inelastic collision. Let V is the final velocity of apple and arrow after the collision. Using the conservation of linear momentum as :
So, the final velocity of apple and arrow after the collision is 2 m/s.
Answer:
moves into a region of higher potential
Potential difference = 835 V
Ki = 835 eV
Explanation:
given data
initial speed = 400000 m/s
solution
when proton moves against a electric field so that it will move into higher potential region
and
we know Work done by electricfield W is express as
W = KE of proton K
so
q × V = 0.5 × m × v² ......................1
put here va
lue
1.6 × × V = 0.5 × 1.67 × × 400000²
Potential difference V = 1.336 × 10-16 / 1.6 × 10-19
Potential difference = 835 V
and
KE of proton in eV is express as
Ki = V numerical
Ki = 835 eV
Answer:
12
Explanation:
The equation is w= f *d
36=3*d
12=d 12 units is the mass
Answer: acceleration = slope graph velocity vs time
Explanation: if you have the graph of velocity vs time , the slope of that graph equals the acceleration of our object assuming constant acceleration...but remenber por a real object is really hard to keep constant acceleration
Answer:
Explanation:
given,
speed of length of travel = 0.86 c
length of tunnel = 88 m
Assume length of super train = 205 m
An observer at rest in the tunnel's reference frame will observe the train's length to be contracted:
L' = L₀ / γ
L' is the length the observer measures,
L₀ is the proper length of the train