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soldier1979 [14.2K]
2 years ago
15

A cube (V = 12 cm³) is lowered in water at 0.2 m.s-¹, using a string. Density of the cube is 4170 kg.m-³. What is the tension in

the string?​
Physics
1 answer:
Bingel [31]2 years ago
6 0

hi hai na usne bheji to make sure to Manas he has to

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If a hockey player starts from rest and accelerates at a rate of 2.1 m/s2 how long does it take him to skate 30m
OLga [1]
Hello!

<span>Let us apply the time function of space, in the uniform uniform motion (UUM)
</span>
Formula: S = S_{o} +  V_{o}* t + a* \frac{t^2}{2}

Data:
S (Final position) = 30 m
So (Initial Position) = 0 m
Vo (Initial velocity) = 0 m/s
t (time) = ? (in seconds)
a (acceleration) = 2.1 m/s²

Solving:
S = S_{o} + V_{o}* t + a* \frac{t^2}{2}
30 = 0 + 0*t + 2.1* \frac{t^2}{2}
30 =  \frac{2.1t^2}{2}
30*2 = 2.1t^2
60 = 2.1t^2
2.1t^2 = 60
t^2 =  \frac{60}{2.1}
t^2 \approx 28.5
t \approx  \sqrt{28.5}
\boxed{\boxed{t \approx 5.3\:s}}\end{array}}\qquad\quad\checkmark

Answer:
<span>C. 5.3s</span>
5 0
4 years ago
The automobile has a weight of 2700 lb and is traveling forward at 4 ft&gt;s when it crashes into the wall. If the impact occurs
alex41 [277]

Answer:

F_b=153918\, lb.ft.s^{-2}

Explanation:

Given:

mass, m=2700 \,lb

time, t=0.06\,s

velocity, v=4\,ft.s^{-1}

coefficient of kinetic friction between wheels & pavement, \mu=0.3

According to first condition,

F\times \Delta t=m\times v

F\times 0.06= 2700\times 4

F=180000\,lb.ft.s^{-2}

According to second condition,

<u>Magnitude of frictional force (which acts opposite to the direction of motion):</u>

f=\mu.N

where N is the normal reaction.

f=0.3\times 2700\times 32.2

f=26082 \,lb.ft.s^{-2}

Now, the impulsive force on the wall if the brakes were applied during the crash:

F_b= F-f

F_b=180000-26082

F_b=153918\, lb.ft.s^{-2}

3 0
4 years ago
HELP ASAP PLSSSS
lubasha [3.4K]

Answer:

A) Burning fossil fuels pollutes the environment

4 0
3 years ago
Read 2 more answers
If a rock on a cliff starts with 3,000 J of GPE and 0 J of KE and ends with 0 J of GPE and 5,000 J of KE, what law of physics wo
alexgriva [62]

The law of physics that this scenario would violate is the law of conservation of energy.

<h3>What is the law of conservation of energy?</h3>

The law of conservation of energy states that energy possessed by an object or physical body can neither be created nor destroyed but can only be transformed from one form to another.

This ultimately implies that, the energy possessed by the rock at the beginning must be equal to the energy possessed by the rock at the end in accordance with the law of conservation of energy.

Read more on energy here: brainly.com/question/1242059

6 0
2 years ago
Un contenedor de 1800 N está en reposo sobre un plano inclinado a 28°, el coeficiente de fricción entre el contenedor y el plano
babunello [35]

Answer:

F = 1480.77N

Explanation:

In order to calculate the required force to push the container with a constant velocity, you take into account the the sum of force on the container is equal to zero. Furthermore, you have for an incline the following sum of forces:

F-Wsin\alpha-F_r=0\\\\F-Wsin\alpha-N\mu cos\alpha=0\\\\F-Wsin\alpha-W\mu cos\alpha=0     (1)

F: required force = ?

W: weight of the container = 1800N

N: normal force = weigth

α: angle of the incline = 28°

g: gravitational acceleration = 9.8m/s^2

μ: coefficient of friction = 0.4

You solve the equation (1) for F and replace the values of the other parameters:

F=W(sin\alpha+\mu cos\alpha)\\\\F=(1800N)(sin28\°+(0.4)cos28\°)=1480.77N

The required force to push the container for the incline with a constant velocity is 1480.77N

8 0
3 years ago
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