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rjkz [21]
2 years ago
7

HELP ME ⟟ WILL BRAINIEST

Mathematics
2 answers:
exis [7]2 years ago
8 0

Answer:

I think the volume is 31.5.

Step-by-step explanation:

Since you didn't include the original numbers for the base area, I just square rooted 9 because there's no other number other than 1 that you would multiply to get 9. Since volume is L*W*H I put 3 for the w and h (because 3*3 is 9) and then I multiplied 9 by 3.5 or 3 and 1/2 (the same thing) to get 31.5. So the volume is 31.5.

4vir4ik [10]2 years ago
8 0

Answer:

I think the volume is 31.5.

Hope this helps bro

Step-by-step explanation:

You might be interested in
Plz help...<br> 6b - 49 =2(b - 3)
wel
You always start by simplifying.
6b-49=2<span>(</span>b-3) becomes 6b-49=2b-6
From there you can group the b's together by subtracting 2b from both sides, leaving you with 4b-49=-6
Now you can get the b's alone by adding 49 (to cancel out -49) to both sides, giving you 4b=43, You're still trying to get b by itself, so what you'll do is divide both sides by 4, giving you b=10.75
5 0
3 years ago
Read 2 more answers
Can you help me please? ​
Anarel [89]

Answer:

C(x)=25x+6000

b=2250

Step-by-step explanation:

C(x)=mx+b

m-marginal cost

x-no items

finding B

C(x)mx+b

6000=25(130)+b

b=2250

General substitution

C(x)=25x+6000

8 0
3 years ago
PLEASE HELP MEE I CAN'T SOLVE THIS BY MYSELF!
UNO [17]

Answer:

x = 22

Step-by-step explanation:

The figure is attached below.

Its given that SV is parallel to RU. We have to find the value of x.

Observe that, if we join point V to U, we will obtain a parallelogram RSVU. One of the properties of a parallelogram is that the sum of its two adjacent angles is always 180 degrees.

So, the two adjacent angles would be: ∠S and ∠R

From the figure:

∠S = 5x + 4

∠R = 44 + x

Since,

∠S + ∠R must be 180 degrees, we can write:

∠S + ∠R  = 180

5x + 4 + 44 + x = 180

6x + 48 = 180

6x = 132

x = 22

Therefore, the value of x is 22.

6 0
3 years ago
Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
Read 2 more answers
How do the values of the 1s in 14.937 and 6.1225 compare?
Darina [25.2K]

Answer:

I would say the answer is b

Step-by-step explanation:

8 0
3 years ago
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