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rjkz [21]
2 years ago
7

HELP ME ⟟ WILL BRAINIEST

Mathematics
2 answers:
exis [7]2 years ago
8 0

Answer:

I think the volume is 31.5.

Step-by-step explanation:

Since you didn't include the original numbers for the base area, I just square rooted 9 because there's no other number other than 1 that you would multiply to get 9. Since volume is L*W*H I put 3 for the w and h (because 3*3 is 9) and then I multiplied 9 by 3.5 or 3 and 1/2 (the same thing) to get 31.5. So the volume is 31.5.

4vir4ik [10]2 years ago
8 0

Answer:

I think the volume is 31.5.

Hope this helps bro

Step-by-step explanation:

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33 1/3% of what number is 21
frutty [35]
It would be 63, because 33 1/3% is the equivalent of 1/3,
21x3 = 63
6 0
3 years ago
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X=-1 a solution to 2(x-4)-5x =-5?
Afina-wow [57]

Answer:

X is equal to -1.

Step-by-step explanation:

bet

4 0
3 years ago
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Which sequences are geometric? Check all that apply.
IRISSAK [1]
There are no options, but I would assume that these sequences would be geometric: 16, -8, 4, -2, 1 -15, -18, -21.6, -25.92, -31.104, 625, 125, 25, 5, 1 can possibly be the correct ones.
3 0
3 years ago
What is f(x) = 7x2 + 42x written in vertex form?
amid [387]

Answer:

\boxed{\boxed{y = 7(x+3)^2-63}}

Step-by-step explanation:

The general vertex form of parabola is,

y=a(x-h)+k

where,

(h, k) is the vertex of the parabola.

The given function is,

\Rightarrow f(x) = 7x^2 + 42x

\Rightarrow y = 7x^2 + 42x

\Rightarrow y = 7(x^2 + 6x)

\Rightarrow y = 7(x^2 + 2\cdot x\cdot 3)

\Rightarrow y = 7(x^2 + 2\cdot x\cdot 3+3^3-3^2)

\Rightarrow y = 7(x^2 + 2\cdot x\cdot 3+3^3)-7\cdot 3^2

\Rightarrow y = 7(x+3)^2-7\cdot 9

\Rightarrow y = 7(x+3)^2-63

This is vertex form the given function.

7 0
3 years ago
Read 2 more answers
Axis of symmetry: x=4; points: (3,-2), (6,-26); opening downward
Andru [333]
Vertex form is
y=a(x-h)^2+k
vertex is (h,k)
axis of symmetry is x=4, therfor h=4
y=a(x-4)^2+k

we have some points
(3,-2) and (6,-26)
input and solve for a and k

(3,-2)
-2=a(3-4)^2+k
-2=a(-1)^2+k
-2=a(1)+k
-2=a+k

(6,-26)
-26=a(6-4)^2+k
-26=a(2)^2+k
-26=a(4)+k
-26=4a+k

we have

-2=a+k
-26=4a+k
multiply first equation by -1 and add to second

2=-a-k
<u>-26=4a+k +</u>
-24=3a+0k

-24=3a
divide both sides by 3
-8=a

-2=a+k
-2=-8+k
add 8 to both sides
6=k

the equation is
y=-8(x-4)^2+6
3 0
3 years ago
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