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cestrela7 [59]
3 years ago
14

Really could use the help

Mathematics
1 answer:
SVEN [57.7K]3 years ago
7 0
c squared= a squared+b squared so c squared=25+64 so the answer would be the square root of 89. Hope this helps!!
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I would love some help here
solniwko [45]

Answer:

first

Step-by-step explanation:

3 0
2 years ago
Nathan goes to the store and buys 2 shorts and 4 shirts for 70$. He later goes to the same store and buys 3 shorts and 3 shirts
Roman55 [17]

Answer:

Each item of clothing costs $12.50

6 0
2 years ago
Reggie Means invested part of $31,000 in municipal bonds that earn 7.5% annual simple interest and the remainder of the money in
insens350 [35]

Answer:

Principal Invested in Municipal Bonds is $16,000

Principal Invested in Corporate Bonds is $15,000

Step-by-step explanation:

If;

Principal Invested in municipal bonds = a

Principal Invested in corporate bonds = b

then we have;

a + b = $31,000 --------------------------------Equation 1

0.075a + 0.085b = $2,475  ---------------Equation 2

From equation 1 we have;

a = 31,000 - b

By putting the values of a in Equation 2 we get;

0.075 (31,000 - b) + 0.085b = 2,475

2,325 - 0.075b + 0.085b = 2,475

0.01b = 150

b = $15,000

By putting the values of b in equation 1 we get;

a = $16,000

4 0
2 years ago
Casey bought a 15.4 pound turkey and an 11.6 pound ham for Thanksgiving and paid $38.51.
White raven [17]

Answer:

h =  1.74

t =  1.19

Step-by-step explanation:

15.4t + 11.6h = 38.51

10.2t + 7.3h = 24.84

15.4•t + 11.6•h = 38.51

10.2•t + 7.3•h = 24.84

11.6h+15.4t = 38.51

7.3h+10.2t = 24.84

h = 87

50

= 1.74

t = 119

100

= 1.19

6 0
2 years ago
Which of the following is an example of a matched pairs design? A. A teacher calculates the average scores of students on a pair
Mashutka [201]

Answer:

B. A teacher compares the pre-test and post-test scores of students

Step-by-step explanation:

the answer is true, because it is a good example to compare the tests between students, we know that a matching pair design is a random model and is used when the experiment allows grouping subjects in pairs based on a variable and each pair will receive randomly a different handling, the answer A is not true because in the example all students are uniformly averaged and the variable is not correlated with subgroups, option c is incorrect because the variable was not randomized and generates classification bias and the option d is incorrect because the teacher compares a small sample as her class with a score of a total sample, but does not intervene on her students when selecting the corresponding group

5 0
3 years ago
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