The range of a logarithmic function is all real numbers, so any transformation won't change it. Hence the range of the given function is also all real numbers.
The logarithm of a function log a = x is also expressed as 10^x = a. In this case, we are given log (x) = -0.123. Hence the equivalent function is 10^-0.123 = x; x is equal to 0.7536. the answer to this problem is 0.7536.
Answer:
y = -5/4x - 7
Step-by-step explanation:
First, find the slope:
3 - -7 / -8 - 0 = -5/4
Put it in point slope form:
y + 7 = -5/4(x-0)
y + 7 = -5/4x
y = -5/4x - 7
Answer:
![a = 2^\alpha.14 \ ,\alpha\geq 8\\b = 7^\delta.14 \ , \delta\geq 3](https://tex.z-dn.net/?f=a%20%3D%202%5E%5Calpha.14%20%5C%20%2C%5Calpha%5Cgeq%208%5C%5Cb%20%3D%207%5E%5Cdelta.14%20%5C%20%2C%20%5Cdelta%5Cgeq%203)
Step-by-step explanation:
As 2 and 7 are the only prime divisors of both
and
we know that both can be written as:
![a = 2^\alpha . 7^\beta \ , \alpha ,\beta\ \in \mathbb{N}_{0}\\b = 2^\gamma . 7^\delta \ , \gamma ,\delta\ \in \mathbb{N}_{0}\\](https://tex.z-dn.net/?f=a%20%3D%202%5E%5Calpha%20.%207%5E%5Cbeta%20%5C%20%2C%20%5Calpha%20%2C%5Cbeta%5C%20%5Cin%20%5Cmathbb%7BN%7D_%7B0%7D%5C%5Cb%20%3D%202%5E%5Cgamma%20.%207%5E%5Cdelta%20%5C%20%2C%20%5Cgamma%20%2C%5Cdelta%5C%20%5Cin%20%5Cmathbb%7BN%7D_%7B0%7D%5C%5C)
Where
is the set of all natural numbers adding the zero (careful because this part is important as I'll explain next).
We also know that 14 divides both numbers and that is actually the greatest common divisor between them. So we can rewrite a and b as follows:
![a = 2^\alpha . 7^\beta.14 \ , \alpha ,\beta\ \in \mathbb{N}_{0}\\b = 2^\gamma . 7^\delta.14 \ , \gamma ,\delta\ \in \mathbb{N}_{0}\\](https://tex.z-dn.net/?f=a%20%3D%202%5E%5Calpha%20.%207%5E%5Cbeta.14%20%5C%20%2C%20%5Calpha%20%2C%5Cbeta%5C%20%5Cin%20%5Cmathbb%7BN%7D_%7B0%7D%5C%5Cb%20%3D%202%5E%5Cgamma%20.%207%5E%5Cdelta.14%20%5C%20%2C%20%5Cgamma%20%2C%5Cdelta%5C%20%5Cin%20%5Cmathbb%7BN%7D_%7B0%7D%5C%5C)
Why do I write them like this? Because this way is easier to observe that if
and
were both greater than zero, then 28 would divide both hence 14 wouldn't be their g.c.d.. Likewise, if
and
were both greater than zero, then 98 would divide both and once again, 14 wouldn't be their g.c.d.
So either of them has to be equal to zero. And then we have that
![a = 2^\alpha.14 \\b = 7^\delta.14](https://tex.z-dn.net/?f=a%20%3D%202%5E%5Calpha.14%20%5C%5Cb%20%3D%207%5E%5Cdelta.14)
All we have left to do is find the possible values for
and
so that
and that only happens if
and ![\delta\geq 3](https://tex.z-dn.net/?f=%5Cdelta%5Cgeq%203)
To answer this question you would start with 1 whole piece and break it into 4 equal pieces. Each piece would be 1/4 of the original.
If you used 3 of these, you are left with 1/4.
Out of the 1/4 leftover, you create 5 equal-sized pieces.
1/4 divided by 5.
1/4 x 1/5 = 1/20 of the original board for each.