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vredina [299]
3 years ago
14

What is the area of this parallelogram? in or in2

Mathematics
2 answers:
Svet_ta [14]3 years ago
8 0

Answer:

answer: 20

Step-by-step explanation:

To find the area of a parellologram you just have to do base × height are base here is 10 and our height is 2 so 10 × 2 = 20 So 20 is the area! Hope that helps/explains well!

Gelneren [198K]3 years ago
6 0
20 in ^2 (I’m pretty sure)
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Henry measured a line to be 7.8 inches long. If the actual length of the line is 7.4 inches, then what was the percent error of
Margarita [4]
The percent error of the measurement is 5.4%
3 0
2 years ago
JKL is a straight line.
kirza4 [7]

Answer:

x = 32°

Step-by-step explanation:

∆KLM is an isosceles triangle because it has two equal sides, KL & KM. Therefore, the angles opposite to each of the two equal sides, which are referred to as the base angles are congruent to each other.

m<KML = m<KLM = 58°

m<MKL = 180 - (58 + 58) (Sum of triangle)

m<MKL = 64°

m<JKM = 180 - m<MKL (linear pair theorem)

m<JKM = 180 - 64 (Substitution)

m<JKM = 116°

∆JKM is also an isosceles triangle with two equal sides. Therefore, it's based angles (x & <J) would also be equal to each other.

Thus:

x = ½(180 - m<JKM)

x = ½(180 - 116) (Substitution)

x = 32°

3 0
3 years ago
What is the value of -16 +9?
ki77a [65]

Answer

the answer is -7

Step-by-step explanation: −(16−9) =-7

6 0
3 years ago
Please I need some answers one or two are fine
Svetlanka [38]

Answer:

A. 10,000

B. 1,000,000

C. 10,000,000,000

D. 1,000,000,000,000

Step-by-step explanation:

10,000/ 10∧4 = 1

1,000,000/ 10∧6 = 1

10,000,000,000/ 10∧10 = 1

1,000,000,000,000/ 10∧12 = 1

Hope this helps! Good luck!

7 0
3 years ago
M1 Matrix is:
harkovskaia [24]

Answer:

(a)First Row, First Column =1

(b)First Row, second Column =0

(c)Second Row, First Column =0

(d)Second Row, second Column =1

Step-by-step explanation:

Given matrix M=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)

The Inverse of a 2X2 matrix

A=\left(\begin{array}{ccc}a&b\\c&d\end{array}\right)

can be found using the following:

A^{-1}=\dfrac{1}{ad-bc} \left(\begin{array}{ccc}d&-b\\-c&a\end{array}\right)

Therefore:

M^{-1}=\dfrac{1}{(5*-5)-(3*-8)} \left(\begin{array}{ccc}5&-3\\8&-5\end{array}\right)\\=-1\left(\begin{array}{ccc}5&-3\\8&-5\end{array}\right)\\=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)

Next, we find the product M^{-1}M

M^{-1}M=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)\\=\left(\begin{array}{ccc}-5*-5+3*-8&-5*3+3*5\\-8*-5+5*-8&-8*3+5*5\end{array}\right)\\=\left(\begin{array}{ccc}1&0\\0&1\end{array}\right)

Therefore:

(a)First Row, First Column =1

(b)First Row, second Column =0

(c)Second Row, First Column =0

(d)Second Row, second Column =1

NOTE: The multiplication of a matrix and its inverse always gives the identity matrix as seen above,

7 0
3 years ago
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