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torisob [31]
1 year ago
8

Two lines, A and B, are represented by the equations given below: Line A: y = x − 6 Line B: y = 3x + 4 Which of the following sh

ows the solution to the system of equations and explains why? (1 point) a (−5, −11), because the point satisfies both equations b (−5, −11), because the point does not lie on any axis c (−3, −5), because the point satisfies one of the equations d (−3, −5), because the point lies between the two axes
Mathematics
1 answer:
nadezda [96]1 year ago
8 0

The solution to the system of linear equations is: (−5, −11).

<h3>What is the Solution to the System of Linear Equations?</h3>

The solution to a system is the x and y -coordinates that satisfies the two linear equations.

Given the linear equations:

Line A: y = x − 6

Line B: y = 3x + 4

Now, equating these two equations

x - 6 = 3x + 4

2x = -10

x = -5

y = -11

Hence, the solution is: (−5, −11), because the point satisfies both equations.

Learn more about solution to a system here:

brainly.com/question/13729904

#SPJ1

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a. 30 percent.

Step-by-step explanation:

Given that:

The standard deviation of returns = 20 percent

Beta = 1.5

Beta=Standard deviation of portfolio × correlation/Standard deviation of market × Correlation

Since Correlation with the market will be +1;

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3 0
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Find the first term and the common ratio <br>third term =6 and seventh term= 96​
mamaluj [8]

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First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: a_n= a_1r^{n-1}

We are given: third term = 6 i,e

a_3=a_1r(3-1)\\6=a_1r^2----eq(1)

Seventh term = 96

a_7=a_1r(7-1)\\96=a_1r^6----eq(2)

Dividing eq(2) and eq(3)

\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}

So, Common Ratio r = 2

Finding First term using eq(1)

a_3=a_1r^2\\6=a_1(2)^2\\6=a_1(4)\\a_1= \frac{6}{4}\\a_1= \frac{3}{2}

So, First term a₁ = 3/2 and common ratio r = 2

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3 years ago
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Answer:

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1). "Opposite angles of a parallelogram are equal"

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2). "Opposite sides of a parallelogram are parallel and equal in measure"

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