If you would like to write the polynomial in standard form, you can do this like this:
4m - 2m^4 - 6m^2 + 9
Writing the polynomial in standard form<span> means that you have to </span>write<span> the terms by descending degree:
</span>- 2m^4 - 6m^2 + 4m + 9
The correct result would be <span>- 2m^4 - 6m^2 + 4m + 9.</span>
Answer:
<h2>A. (0, 4)</h2>
Step-by-step explanation:
The equation of a circle:
(h, k) - center
r - radius
We have the equation:
h = 0, k = 4, r = 5
Find the amount of the discount and divide by the original price:
30-20 = 10
10/30 = 0. 333
Multiply by 100 for percent:
0.333 x 100 = 33.3333%
Round the answer as needed.
9514 1404 393
Answer:
2√30 ∠-120°
Step-by-step explanation:
The modulus is ...
√((-√30)² +(-3√10)²) = √(30 +90) = √120 = 2√30
The argument is ...
arctan(-3√10/-√30) = arctan(√3) = -120° . . . . a 3rd-quadrant angle
The polar form of the number can be written as ...
(2√30)∠-120°
_____
<em>Additional comments</em>
Any of a number of other formats can be used, including ...
(2√30)cis(-120°)
(2√30; -120°)
(2√30; -2π/3)
2√30·e^(i4π/3)
Of course, the angle -120° (-2π/3 radians) is the same as 240° (4π/3 radians).
__
At least one app I use differentiates between (x, y) and (r; θ) by the use of a semicolon to separate the modulus and argument of polar form coordinates. I find that useful, as a pair of numbers (10.95, 4.19) by itself does not convey the fact that it represents polar coordinates. As you may have guessed, my personal preference is for the notation 10.95∠4.19. (The lack of a ° symbol indicates the angle is in radians.)
The domain is the input values, which would also be X values.
{ x |x= -5, -3, 1, 2,6}
