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3 years ago

Solve x2+x-1=0 using the quadratic formula.

Mathematics

1 answer:

weeeeeb [17]3 years ago

6 0

Answer:

x = $\frac{-1 ±\sqrt{5} }{2}$

Step-by-step explanation:

Ignore the A that doesn't belong in the answer

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1. How much time will you save on a ten mile trip if you travel at 60 mph rather than at 55 mph?

Dafna11 [192]

60/10 = 6

so it would take 6 minutes to drive 10 miles

55/10 = 5.5 so it would take 5 and a half minutes to drive 10 miles

6-5.5 = 0.5 so it would save you 30 seconds

4 0

4 years ago

Solve the equation. Explain your steps.

OleMash [197]

Answer:

x=-36

Step-by-step explanation:

x+1=-35 (divide both sides by 5)

x=-36 (subtract 1 from each side)

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3 years ago

omeli [17]

Answer:

instead of lemonade I would drink water

Step-by-step explanation:

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3 0

3 years ago

I need help please.. I really will appreciate it!

Rus_ich [418]

Answer: the answer to this is B. 3x^2+4x+7 hopefully I'm correct

3 0

4 years ago

Emil's backpack weighs six and three eights pounds. He removes a book that weighs three fourth pound. Then he removes a book tha

Leona [35]

Answer:

Emil's back pack weigh now $5\frac{1}{8}\ pounds$ .

Step-by-step explanation:

Given:

Total Weight of backpack = $6\frac{3}{8}\ pounds$

$6\frac{3}{8}\ pounds$ can be Rewritten as $\frac{51}{8}\ pounds$

Weight of backpack = $\frac{51}{8}\ pounds$

Weight of Book 1 = $\frac{3}{4}\ pound$

Weight of Book 2 = $\frac{1}{2}\ pound$

We need to find weight of back pack after removing books.

Solution:

Now we can say that;

weight of back pack after removing books can be calculated by Subtracting Weight of Book 1 and Weight of Book 2 from Total Weight of backpack.

framing in equation form we get;

weight of back pack after removing books = $\frac{51}{8}-\frac{3}{4}-\frac{1}{2}$

Now to solve the equation we will first make the denominator common using LCM.

weight of back pack after removing books = $\frac{51\times1}{8\times1}-\frac{3\times2}{4\times2}-\frac{1\times4}{2\times4}=\frac{51}{8}-\frac{6}{8}-\frac{4}{8}$

Now the denominators are common so we will solve the numerator.

weight of back pack after removing books = $\frac{51-6-4}{8}=\frac{41}{8}\ pounds \ \ OR \ \ 5\frac{1}{8}\ pounds$

Hence Emil's back pack weigh now $5\frac{1}{8}\ pounds$ .

6 0

3 years ago